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fomenos
4 years ago
9

How do you write 3.27 as a decimal number rounded to the nearest thousandth

Mathematics
2 answers:
yawa3891 [41]4 years ago
5 0
3.27 rounded to the nearest thousandth is 3.270~
hichkok12 [17]4 years ago
5 0
Since 3.272727 is repeating, the thousandth place would be the second 2. since the number behind it is 7, that means we can round up the 2 to a 3. so the answer would be 3.273
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The perimeters of two similar figures are 15 in. and 24 in. What is the ratio of the areas of the two figures? State your answer
kkurt [141]

Answer:

25/64

Step-by-step explanation:

ratio of perimeters = 15/24 = 5/8

ratio of areas = square of ratio of perimeters

ratio of areas = (5/8)^2 = 25/64

5 0
3 years ago
A= h(b+c) solve for b
madreJ [45]
A=h(b+c)
A/h=b+c
b=(A/h)-c

Answer: b=(A/h)-c
7 0
3 years ago
Read 2 more answers
4. A triangle with base (2x+2) and height (x-2) is cut out of a rectangular sheet of paper that is (3x+4) by (2x+3) what is the
juin [17]
So what we do is
area that remains=total area-triangle area that was cut out


we need to find 2 things
total area
triangle area

total area=rectange=base times height
area=(3x+4) times (2x+3)
FOIL or distribute
6x^2+8x+9x+12=6x^2+17x+12

triangle area=1/2 times base times height
triangle area=1/2 times (2x+2) times (x-2)=
(x+2) times (x-2)=x^2+2x-2x-4=x^2-4


so
total area=6x^2+17x+12
triangle area=x^2-4

subtract
area that remains=total area-triangle area that was cut out
area that remains=6x^2+17x+12-(x^2-4)=
6x^2+17x+12-x^2+4=
6x^2-x^2+17x+12+4=
5x^2+17x+16


area that remains is 5x^2+17x+16

5 0
3 years ago
Linear functions written in the form Ax + By = C are written in slope-intercept form.
Gemiola [76]

Answer:

false

Step-by-step explanation:

slope and intercept equation is y=mx+c

8 0
4 years ago
A poll of 1,000 randomly selected registered voters was taken and 680 responded that they favor candidate X for mayor (p 1 = 0.6
Zielflug [23.3K]

Answer:

The interval (-0.0199, 0.0510) represents the region of values where the true difference (in population terms now) between the initial proportion of registered voters that favour candidate X and the proportion of registered voters that favour candidate X just before election can take on with a confidence level of 90%.

Step-by-step explanation:

Confidence Interval for the population proportion is basically an interval of range of values where the true population proportion can be found with a certain level of confidence. It is usually obtained from the sample.

p₁ represents the proportion of registered voters that favour candidate X in the initial poll, way before the election.

p₂ represents the proportion of registered voters that favour candidate X in the poll just before the election.

So, for this question the confidence interval for the true difference between the population proportion of registered voters that favour candidate X way before the elections and the population proportion that favour candidate X just before the election lies within (-0.0199, 0.0510) with a confidence interval of 90%.

Confidence interval is calculated mathematically as thus:

Confidence Interval = (Difference in Sample proportion) ± (Margin of error)

Margin of Error is the width of the confidence interval about the difference in the two sample proportions.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error)

Critical value = 1.645 (obtained from the z-tables because the sample size is large enough to ignore that information about the population standard deviation isn't given and t-critical value approximates z-critical value)

Hope this Helps!!!

4 0
3 years ago
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