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larisa [96]
3 years ago
13

3x41 using standard algorithm

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
7 0
41
X 4
=
164 that the answer using standard Algorithm
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Assume the following values for the diagrams below: Q1 = 15 bags. Q2 = 10 bags. Q3 = 22 bags. The market equilibrium price is $2
Basile [38]

Answer:

Step-by-step explanation:

a. $360

The total surplus of Q1 is found within triangle abc. The base is a ($70) to c ($10), and the height is the x value of b, or Q1 (12 bags). The total length of the base is 60 (70-10). Multiply that by the height of the triangle (12), and divide the total by 2. (60 x 12) / 2 = 360

a1. $144

The consumer surplus for Q1 is found within the triangle formed by point a, point b, and the y intercept of the equilibrium. The problem says equilibrium = 46, so the third is point (0, 46). The base is point a ($70) to the equilibrium intercept ($46). The height is Q1 (12). The total base is 24 (70-46). (24 x 12) / 2 = 144

b. $62.50

The deadweight loss for Q2 is found is found within triangle dbe. The base is d ($56) to e ($31). The height of the triangle is Q2 (7) to Q1 (12). The total base is 25 (56-31), and the total height is 5 (12-7). (25 x 5) / 2 = 62.5

b1. $297.50

The total surplus of Q2 is found by subtracting the deadweight loss from the total surplus. 360 - 62.5 = 297.5

c. $122.50

The deadweight loss for Q3 is found within triangle bfg. The base is f (67) to g (32). The height is Q1 (12) to Q3 (19). The total base is 35 (67-32) and the total height is 7 (19-12). (35 x 7) / 2 = 122.5

c1. $237.50

The total surplus for Q3 is found by subtracting the deadweight loss from the total surplus. 360 - 122.5 = 237.5

8 0
2 years ago
2x-4 (x-4)=-2+3x+3 what's the value of x
chubhunter [2.5K]
2x - 4(x-4) = -2 + 3x + 3
2x - 4x + 16 = 3x + 1
-2x + 16 = 3x + 1
5x = 15
x = 3
6 0
3 years ago
Read 2 more answers
Maths Answers please <br>4p-p
solniwko [45]

Answer:

<h2>               3p</h2>

Step-by-step explanation:

4p - p = 4p - 1p = (4 - 1)p = 3p

3 0
3 years ago
Read 2 more answers
Cna i get some help with dis plz
Tomtit [17]

Let b_1,b_2,\ldots,b_{20} be the 20 marks of the boys, and g_1,g_2,\ldots,g_{10} be the 10 marks of the girls.

We know that the global mean was 70, meaning that

\dfrac{b_1+b_2+\ldots+b_{20}+g_1+g_2+\ldots+g_{10}}{30}=70

Multiplying both sides by 30 we deduce that the sum of the scores of the whole classroom is

b_1+b_2+\ldots+b_{20}+g_1+g_2+\ldots+g_{10}=2100

By the same logic, we work with the marks of the boys alone: we know the average:

\dfrac{b_1+b_2+\ldots+b_{20}}{20}=62

And we deduce the sum of the marks for the boys:

b_1+b_2+\ldots+b_{20}=1240

Which implies that the sum of the marks of the girls is 2100-1240=860

And finally, the mean for the girls alone is

\dfrac{860}{10}=86

6 0
3 years ago
A company is designing a new cylindrical water bottle. The volume of the bottle will be 179 cmcubed. The height of the water bot
tresset_1 [31]

Answer:

The radius of the water bottle is 2.72cm

Step-by-step explanation:

In this question, we are concerned with calculating what the radius of the cylindrical water bottle is given its volume and height.

Mathematically, the volume of a cylinder is V = pi * r^2 * h

From the question, we know that V = 179 cm^3. , h = 7.7cm while r = ?

we substitute these values into the volume equation.

179 = pi * r^2 * 7.7

179 = 3.14 * r^2 * 7.7

179 = 24.178 * r^2

r^2 = 179/24.178

r^2 = 7.403

r = square root 7.403

r = 2.72 cm

7 0
3 years ago
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