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3 years ago

I am stuck at this question

Mathematics

1 answer:

Marrrta [24]3 years ago

6 0

Answer:

Step-by-step explanation:

B(2,10); D(6,2)

Midpoint(x1+x2/2, y1+y2/2) = M ( 2+6/2, 10+2/2) = M(8/2, 12/2) = M(4,6)

Rhombus all sides are equal.

AB = BC = CD =AD

distance = √(x2-x1)² + (y2- y1)²

As A lies on x-axis, it y-co ordinate = 0; Let its x-co ordinate be x

A(X,0)

AB = AD

√(2-x)² + (10-0)² = √(6-x)² + (2-0)²

√(2-x)² + (10)² = √(6-x)² + (2)²

√x² -4x +4 + 100 = √x²-12x+36 + 4

√x² -4x + 104 = √x²-12x+40

square both sides,

x² -4x + 104 = x²-12x+40

x² -4x - x²+ 12x = 40 - 104

8x = -64

x = -64/8

x = -8

A(-8,0)

Let C(a,b)

M is AC midpoint

(-8+a/2, 0 + b/2) = M(4,6)

(-8+a/2, b/2) = M(4,6)

Comparing;

-8+a/2 = 4 ; b/2 = 6

-8+a = 4*2 ; b = 6*2

-8+a = 8 ; b = 12

a = 8 +8

a = 16

Hence, C(16,12)

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3 years ago

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Answer:

almost 0%

Step-by-step explanation:

Given that for an insurance company with 10000 automobile policy holders, the expected yearly claim per policyholder is $240 with a standard deaviation of 800

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2 years ago

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2. Suppose $x+6$ . Then $|x+6|=-(x+6)=-x-6$ and

$-x-6=\dfrac14\implies x=-\dfrac{25}4$

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- - -

For the question regarding inequality, you know that the absolute value must return a non-negative number. In other words, there is no $x$ such that $|x|$ .

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2 years ago

I am stuck at this question​

I am stuck at this question