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AfilCa [17]
1 year ago
12

Answer choices 6 cubic units8 cubic units 10.6 cubic units 18 cubic units

Mathematics
1 answer:
antiseptic1488 [7]1 year ago
7 0

Given,

Cylinder A has a volume of 6 cubic units

and height =3 units

The radius of cylinder A,

\begin{gathered} r=\sqrt[]{\frac{V}{\pi h}} \\ =\sqrt[]{\frac{6}{3\pi}} \\ =0.8 \end{gathered}

To find the volume of a cylinder B

\begin{gathered} V=\pi r^2h \\ =(3.14)\times(0.8)^2\times(3) \\ =6.03 \end{gathered}

Thus the volume of cylinder B is 6.03

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A part time seamstress made $8881.93 last year. If she claimed herself as an exemption for $3650 and had a $5700 standard deduct
Rainbow [258]

Answer:

c

Step-by-step explanation:

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3 years ago
jan, mya, and Sara ran a total of 64 miles last week. jan and mya ran the same number of miles. Sara ran 8 less miles than mya.
Debora [2.8K]
So,

We'll just use A to represent both Jan and Mya's miles, since they ran the same number.

We have the equations:
1. Jan (J) = Mya (M)
2. Sara (S) = M - 8
3. 2A + S = 64
J = M
S = M - 8

We'll just use A to represent both J and M.

S = M - 8

We'll use Elimination by Substitution.
2A + A - 8 = 64

Collect Like Terms
3A - 8 = 64

Add 8 to both sides
3A = 72

Divide both sides by 3
A = 24

Since
A = J
and
A = M
and
J = M
then
J = 24
M = 24

Substitute
S = 24 - 8
S = 16

Check
24 + 24 + 16 = 64
64 = 64 This checks.

So,
J = 24
M = 24
S = 16
4 0
3 years ago
Read 2 more answers
Find the length of the altitude to the hypotenuse. Round the answer to the nearest tenth, if needed.
SVEN [57.7K]
To solve this, it might be easier to draw it out (see the picture below). I split it into two triangles and used trig functions to find the altitude. I used the big triangle to find theta, and the used theta to find the side of the altitude. *remember that sine= opposite/hypotenuse*

8 0
3 years ago
Math question try your best do not guess
Juli2301 [7.4K]

Answer:

The answer would be 2,187

1). solution

3³÷3^(-4)

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2,187

5 0
3 years ago
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A movie theater charges $15 for standard viewing, $20 for 3D viewing, and $35 for Dinner and a
Ludmilka [50]

The quantity of each type of seats sold are as follows:

  • Standard viewing = 2000

  • 3D seats = 800

  • Movie and a dinner seat = 200

According to the question,there are four times as many 3D, x seats as Dinner and a Movie, y seats.

That is, x = 4y

Also, total seats

= (x) + (y) + (z) = 3000...….............eqn(1)

Also, If the theater brings in $53,000 when tickets to all 3000 seats are sold.

  • 20x + 35y + 15z = 53000...........eqn(2)

By substituting 4y for x in equations 1 and 2; we have;

<em>5y + z = 3000</em>..…........eqn(3) and

<em>115y + 15z = 53000</em>.........eqn(4)

By solving equations 3 and 4 simultaneously; we have;

y = 200 and z = 2000

and since x = 4y

x = 800

The quantity of each type of seats sold is as follows:

  • Standard viewing = 2000

  • 3D seats = 800

  • Movie and a dinner seat = 200

Read more:

brainly.com/question/12413726

5 0
3 years ago
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