Answer:
Step-by-step explanation:
A binary string with 2n+1 number of zeros, then you can get a binary string with 2n(+1)+1 = 2n+3 number of zeros either by adding 2 zeros or 2 1's at any of the available 2n+2 positions. Way of making each of these two choices are (2n+2)22. So, basically if b2n+12n+1 is the number of binary string with 2n+1 zeros then your
b2n+32n+3 = 2 (2n+2)22 b2n+12n+1
your second case is basically the fact that if you have string of length n ending with zero than you can the string of length n+1 ending with zero by:
1. Either placing a 1 in available n places (because you can't place it at the end)
2. or by placing a zero in available n+1 places.
0 ϵ P
x ϵ P → 1x ϵ P , x1 ϵ P
x' ϵ P,x'' ϵ P → xx'x''ϵ P
Answer:
155.53
Step-by-step explanation:
I know where this question is from hahaha
The answer to your question is 3
Reasons : -9+ 3•4= -9+12= 3.
Answer:
the roots are {-4/3, 4/3}
Step-by-step explanation:
Begin the solution of 11=6|-2z| -5 by adding 5 to both sides:
11=6|-2z| -5 becomes 16 = 6|-2z|.
Dividing both sides by 12 yields
16/12 = |-z|
There are two cases here: first, that one in which z is positive and second the one in which z is negative.
If z is positive, 4/3 = -z, and so z = -4/3, and:
If z is negative, 4/3 = z
Thus the roots are {-4/3, 4/3}
Answer:
You would just plug in the x’s for the equations above and that will equal your x
Step-by-step explanation:
for example x=1
the equation is x+5
so y equals 1+5=6
y=6
