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antiseptic1488 [7]
3 years ago
11

If 3+4+8=15 then 8+3+4=15 right?

Mathematics
1 answer:
Vlada [557]3 years ago
4 0
Yes same thing

love ya
~~~~~~~
Frankie❤
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A bag contains 14 blue, 6 red, 12 green, and 8 purple buttons. 25 buttons are removed from the bag randomly. How many of the rem
sergeinik [125]

Answer:

1 button.

Step-by-step explanation:

Total buttons = 40

Total red buttons = 6

Total Buttons removed =25

Buttons left = 40–25 = 15

Let the red buttons left = x

1.)Then, the probability of red buttons after removing 25 buttons = x/15 outcome / Total outcome)

2.)Probability of red buttons in the bag after removing 25 buttons is 1/3 (As given in the question)

Comparing Statement 1.) & 2.) , We get

x/15 = 1/3

x = 5

So the red buttons left = 5

Total red buttons= 6

Red buttons removed = 6–5= 1

Hence, only 1 button was red in the 25 removed buttons

5 0
3 years ago
Destiny performs a hypothesis test on a population with µ = 115 and σ = 30. Her sample size is 25 with a mean of 120.4. Which of
Ivenika [448]

z statistic or z score can be calculated using the following formula:

z = (x – u) / (σ / sqrt n)

So simply substitute the given values:

z = (120.4 – 115) / (30 / sqrt 25)

z = 0.90

 

Answer:

<span>b. 0.90</span>

8 0
3 years ago
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Degger [83]

Answer:

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2х + y = 11<br> 4х — Зу = -3<br> What is the solution to this system of equations?
malfutka [58]

Answer:

The answer is x=3 and y=5

Step-by-step explanation:

Step: Solve 2x+y = 11 for y

2x+y=11

2x+y+−2x=11+−2x (Add -2x to both sides)

y=−2x+11

Step: Substitute −2x+11 for y in 4x−3y = −3

4x−3y = −3

4x−3(−2x+11) = −3

10x−33 = −3 (Simplify both sides of the equation)

10x−33+33 = −3+33 (Add 33 to both sides)

10x=30

\frac{10x}{10}  = \frac{30}{10}  (Divide both sides by 10)

x=3

Step: Substitute 3 for x in y = −2x+11

y=−2x+11

y=(−2)(3)+11

y=5 (Simplify both sides of the equation)

Answer:

x=3 and y=5

3 0
3 years ago
Jim went on a fishing holiday.The histogram shows some ingormation about the weights of the fish he caught.
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You did not put the histogram here, so I am not able to help :c
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