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3 years ago

If 3+4+8=15 then 8+3+4=15 right?

Mathematics

1 answer:

Vlada [557]3 years ago

4 0

Yes same thing

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A machine that cost £35,000 is operated 8 hours a day in a 5-day week but one hour each day is used for test purposes. For use o

MArishka [77]

1 hour each day is used for test
so 8-1=7 used per day

so commercial is 1 in the 4:2:1 so
4+2+1=7
ok, so 7 units, 7 hours
4 hour for private
2 hour for research
1 hour of commerical

4*5=20=private
2*15=30=research
1*4=40=commercial

20+30+40=90

percent from commercial
40/90=0.44444444444≈44.44% about 44%

6 0

4 years ago

Read 2 more answers

Determine the y-intercept of the graph of this equation: y - 3 = 2(x + 5)

dimaraw [331]

Answer:

y intercept is 13

Step-by-step explanation:

y - 3 = 2(x + 5)

To find the y intercept, let x=0 and solve for y

y - 3 = 2(0 + 5)

y - 3 = 2(5)

y -3 =10

y-3+3 = 10+3

y = 13

8 0

3 years ago

Anwser: <br> 36÷(1-9×1-4)+1+2

kkurt [141]

So this is a BIDMAS question so first you do what’s in the brackets so you have (1-9x1-4) and you have to do the multiplication first out of that to get (1-9-4) which is -12 so then you have overall 36 / -12 + 1 + 2 so you have to do the division first so do 36/-12 to get -3 and you have -3 + 1 + 2 which is 0 so your answer is 0.

5 0

3 years ago

Read 2 more answers

Please solve this, will rate 5 stars and mark as STAR!

Nina [5.8K]

Answer:

$\boxed{5 \cdot \sqrt{2} \cdot \sqrt[6]{5} }$

Step-by-step explanation:

$\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }$

$\sqrt{\sqrt[3]{10} } \implies (10^\frac{1}{3} )^\frac{1}{2} =10^\frac{1}{6} =\sqrt[6]{10}$

$\therefore \sqrt{\sqrt[3]{10} }=\sqrt[6]{10}$

$\text{Solving }\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }$

$250=2 \cdot 5^3$

$\sqrt[3]{250}=\sqrt[3]{2\cdot 5^3}=5 \sqrt[3]{2}$

Once

$\sqrt[6]{2} \cdot \sqrt[6]{5} = \sqrt[6]{10}$

We have

$5 \sqrt[3]{2} \cdot \sqrt[6]{2} \cdot \sqrt[6]{5}$

We can proceed considering the common base of exponentials

$\sqrt[3]{2} \cdot \sqrt[6]{2} = 2^{\frac{1}{3}} \cdot 2^{\frac{1}{6} } = 2^{\frac{3}{6} } = 2^{\frac{1}{2} }=\sqrt{2}$

Therefore,

$5 \sqrt[3]{2} \cdot \sqrt[6]{2} \cdot \sqrt[6]{5} = 5 \cdot \sqrt{2} \cdot \sqrt[6]{5}$

7 0

3 years ago

A CD with a diameter of 120 millimeters rotates a rate of 45 revolutions per minute. Find the linear speed of the CD in millimet

ale4655 [162]

9514 1404 393

Answer:

16,965 mm/min
90π ≈ 282.7 radians/min

Step-by-step explanation:

The circumference of the CD is ...

C = πd

C = π(120 mm) ≈ 376.99 mm

This is the distance a point on the edge of the CD will travel when making one revolution. It will travel 45 times this far when making 45 revolutions:

(376.99 mm/rev)(45 rev/min) ≈ 16,965 mm/min

There are 2π radians in each revolution, so the angular speed is ...

(2π rad/rev)(45 rev/min) = 90π rad/min ≈ 282.7 rad/min

6 0

3 years ago