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4 years ago

Why is the My Plate constructed in the way it is?

1 answer:

8 0

My Plate was released to replace the food pyramid and displays the five main food groups. The plate visually shows approximate proportions of the different food groups as opposed tot the food pyramid.

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(hypochlorous acid) is produced by bubbling chlorine gas through a suspension of solid mercury(II) oxide particles in liquid wat

SVETLANKA909090 [29]

The equilibrium constant expression for this reaction is $K_{eq} = \frac{[HOCl]^{2}}{[Cl_{2}]^{2}}$ . This is an example of a heterogeneous equilibrium wherein the states of the reactants and products are different. In such a case, only the concentration of the gaseous and aqueous substances are included in the equilibrium constant expression.

Further Explanation:

The equilibrium constant expression is the ratio of the concentration of the products and the concentration of reactants.

The guidelines in writing the equilibrium constant expressions are as follows:

Write molar concentration of each product in the numerator of the Keq expression.
Write the coefficient of the substance as the exponent of the molar concentration of the substance in the Keq expression.
Write the molar concentration of each reactant raised to its coefficient in the denominator.

Note: Pure substances (i.e. solids and liquids) are not included in the equilibrium constant expression as their concentrations are constant.

The numerical equivalent of the Keq expression is called the equilibrium constant. It has a specific value for a given temperature. The equilibrium constant provides information about the spontaneity and progress of an equilibrium reaction.

Learn More

Learn more about equilibrium constants brainly.com/question/4137132
Learn more about Le Chatelier's Principle brainly.com/question/12983923
Learn more about Gibbs Free Energy brainly.com/question/12979420

Keywords: equilibrium constant expression, equilibrium

6 0

3 years ago

Solutions of sulfuric acid and lead(II) acetate react to form solid lead(II) sulfate and a solution of acetic acid. 4.90 g of su

GaryK [48]

Answer:

Mass H2SO4 = 3.42 grams

Mass of lead acetate = 0 grams

Mass PbSO4 = 4.58 grams

Mass of CH3COOH = 1.81 grams

Explanation:

Step 1: Data given

Mass of sulfuric acid = 4.90 grams

Molar mass of sulfuric acid = 98.08 g/mol

Mass of lead acetate = 4.90 grams

Molar mass of lead acetate = 325.29 g/mol

Step 2: The balanced equation

H2SO4 + Pb(C2H3O2)2 → PbSO4 + 2CH3COOH

Step 3: Calculate moles

Moles = mass / molar mass

Moles H2SO4 = 4.90 grams / 98.08 g/mol

Moles H2SO4 = 0.0500 moles

Moles lead acetate = 4.9 grams / 325.29 g/mol

Moles lead acetate = 0.0151 moles

Step 4: Calculate the limiting reactant

For 1 mol H2SO4 we need 1 mol lead acetate to produce 1 mol PbSO4 and 2 moles CH3COOH

The limiting reactant is lead acetate. It will completzly be consumed (0.0151 moles). H2SO4 is in excess. There will react 0.0151 moles. There will remain 0.0500 - 0.0151 = 0.0349 moles

Step 5: Calculate moles of products

For 1 mol H2SO4 we need 1 mol lead acetate to produce 1 mol PbSO4 and 2 moles CH3COOH

For 0.0151 moles lead acetate we'll have 0.0151 moles PbSO4 and 2*0.0151 = 0.0302 moles CH3COOH

Step 6: Calculate mass

Mass = moles * molar mass

Mass H2SO4 = 0.0349 moles * 98.08 g/mol

Mass H2SO4 = 3.42 grams

Mass PbSO4 = 0.0151 moles * 303.26 g/mol

Mass PbSO4 = 4.58 grams

Mass of CH3COOH = 0.0302 moles * 60.05 g/mol

Mass of CH3COOH = 1.81 grams

5 0

4 years ago

What mass of CDP (403 g mol−1) is in 10 mL of the buffered solution at the beginning of Experiment 1? 6.4 × 10−4 g 6.4 × 10−3 g

eduard

Compete Question:

What mass of CDP (403 g mol−1) is in 10 mL of the buffered solution at the beginning of Experiment 1?

Passage: "16 mmol of CDP in 1 L of buffer"

Answer:

6.4 × 10-2 g

Explanation:

$Mass = Mole × Molar Mass$

we are given from the question that 16 mmol of CDP is in 1 L of buffer

this mean that we have $16 × 10^-3$ moles of CDP in 1 liter of buffer.

so the mass of CDP in one liter of buffer will be calculate as,

mass of CDP = $16 × 10^-3$ × 403g mol−1

= $64 × 10^-1$

= 6.4 g/L

But because the question

asks us about the mass of CDP in 10 mL of solution, we will go further to calculate it like this:

6.4 g/L × 10 mL

6.4 g/L × 0.01 L = $6.4 × 10^-2$

8 0

4 years ago

Which organelle is the control center of a cell?

Korvikt [17]

C) the nucleus. Hope this helps :)

6 0

3 years ago

Read 2 more answers

What is the energy of a 4.66 x 1014 Hz wave?

docker41 [41]

I attached the working and the answer to both questions below.

Please note that E = energy, ν = frequency, h = Plank's Constant

The energy of a 4.66 x 10¹⁴ Hz wave is 3.088 × 10⁻¹⁷ J

4 0

3 years ago