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Makovka662 [10]
3 years ago
7

To 25mL of 0.90M HCl, 275mL do distilled water is added. What is the molarity of the resulting solution?

Chemistry
1 answer:
nalin [4]3 years ago
8 0

Answer:

0.075 M.

Explanation:

  • It is a dilution process.
  • We have the rule states that the no. of millimoles before dilution is equal to the no. of millimoles after dilution.

<em>(MV) before dilution = (MV) after dilution </em>

M before dilution = 0.90 M.

V before dilution = 25.0 mL.

M after dilution = ??? M.

V after dilution = V of HCl + V of water added = 25.0 mL + 275.0 mL = 300.0 mL.

∴ M after dilution = (MV) before dilution / V after dilution = (0.90 M)(25.0 mL) / (300.0 mL) = 0.075 M.

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Answer these questions based on 234. 04360 as the atomic mass of thorium-234. The masses for the subatomic particles are given.
nikdorinn [45]

The mass defect for the isotope thorium-234 if given mass is 234.04360 amu is 1.85864 amu.

<h3>How do we calculate atomic mass?</h3>

Atomic mass (A) of any atom will be calculated as:

A = mass of protons + mass of neutrons

In the Thorium-234:

Number of protons = 90

Number of neutrons = 144

Mass of one proton = 1.00728 amu

Mass of one neutron = 1.00866 amu

Mass of thorium-234 = 90(1.00728) + 144(1.00866)

Mass of thorium-234 = 90.6552 + 145.24704 = 235.90224 amu

Given mass of thorium-234 = 234.04360 amu

Mass defect = 235.90224 - 234.04360 = 1.85864 amu

Hence required value is 1.85864 amu.

To know more about Atomic mass (A), visit the below link:

brainly.com/question/801533

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Differences in air pressure drive the global wind system on earth. Which term describes polar winds that blow from east to west?
marshall27 [118]

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Suppose Gabor, a scuba diver, is at a depth of 15m15m. Assume that: The air pressure in his air tract is the same as the net wat
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Answer:

The ration of molar concentration is "2.5".

Explanation:

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Increase in pressure,

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Now,

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The ratio will be:

=  \frac{(\frac{n}{V})_{15m} }{(\frac{n}{V})_{surface} }

or,

=  \frac{P}{P_s}

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