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Makovka662 [10]
3 years ago
7

To 25mL of 0.90M HCl, 275mL do distilled water is added. What is the molarity of the resulting solution?

Chemistry
1 answer:
nalin [4]3 years ago
8 0

Answer:

0.075 M.

Explanation:

  • It is a dilution process.
  • We have the rule states that the no. of millimoles before dilution is equal to the no. of millimoles after dilution.

<em>(MV) before dilution = (MV) after dilution </em>

M before dilution = 0.90 M.

V before dilution = 25.0 mL.

M after dilution = ??? M.

V after dilution = V of HCl + V of water added = 25.0 mL + 275.0 mL = 300.0 mL.

∴ M after dilution = (MV) before dilution / V after dilution = (0.90 M)(25.0 mL) / (300.0 mL) = 0.075 M.

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For problems 2 &amp; 3, the density of the sample is 0.9977 g/mL and the molar mass of calcium carbonate is 100.0 g/mol. 2. Calc
Alenkasestr [34]
1) Use of density formula to calculate mass of sample, M

D = M / V => M = D* V = 0.9977 g / mL * 50.00 mL = 49.885 g of sample

Realize that the sample is the solution.

2) Use ppm concentration to calculate mass of solute (calcium carbonate)

By definition, 75.0 ppm = 75.0 g of calcium carbonate / 1,000,000 g of solution.

You use that ratio to calculate the mass of calcium carbonate in 49.885 g of solution.

Mass of solute = 49.885 g of solution * [75.0 g of calcium carbonate] / [1,000,000 g of solution] =

Mass of solute =  0.00374 g of calcium carbonate

Answer: 0.00374 g of calcium carbonate
4 0
3 years ago
A volume of 80.0 mL of aqueous potassium hydroxide (KOH) is titrated against a standard solution of sulfuric acid (H2SO4). What
yaroslaw [1]

Answer:

0.478 M

Explanation:

Let's consider the neutralization reaction between KOH and H₂SO₄.

2 KOH + H₂SO₄ → K₂SO₄ + 2 H₂O

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0.0382 moles of KOH are in 80.0 mL. The molarity of KOH is:

M = 0.0382 mol/0.0800 L = 0.478 M

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3 years ago
Explane factor affecting stability of alkene?
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Answer:

Alkenes have substituents, hydrogen atoms attached to the carbons in the double bonds. The more substituents the alkenes have, the more stable they are. Thus, a tetra substituted alkene is more stable than a tri-substituted alkene, which is more stable than a di-substituted alkene or an unsubstituted one.

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Thermal energy relates direction to motion at the molecular level. As the temperature rises, molecules move faster and collide more vigorously, greatly increasing the likelihood of bond cleavages and rearrangements as described above.
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