Answer:
-2.6
Step-by-step explanation:
5x - 5 >/ - 18
5x >/ -13
x>/ -13/5
x>/ -2.6
Answer:
(A) 100 (in thousands)
(B) 180 (in thousand dollars)
Step-by-step explanation:
Given:
profit function as P(q) = -0.02q² + 4q - 20
where,
q is the number of thousands of pairs of sunglasses sold and produced,
P(q) is the total profit in thousands of dollars
To find the point of maxima differentiating the above equation and equating it to zero
P'(q) = - (2)0.02q + 4 - 0 = 0
or
⇒ - 0.04q + 4 = 0
or
⇒ - 0.04q = - 4
or
⇒ q = 100
Hence,
(A) 100 pairs of sunglasses (in thousands) should be sold to maximize profits
(B) Substituting the value of q in the profit function to calculate the actual maximum profit
P(q) = -0.02(100)² + 4(100) - 20
or
P(q) = - 0.02(10000) + 400 - 20
or
P(q) = - 0.02(10000) + 400 - 20
or
P(q) = 180 (in thousands dollar)
120 days in 4 months start day 1 with 4 rats every 4 days 4 rats add on so what I did is this.
Day 1= 4 rats day 4=8 day 8 = 12 so on intell u hit 118 days.but the answer to your question is.. there will be 114 rats if the population of rats double every 4 days for 4 months. hope this is correct and helps. :)
Answer:
1
Step-by-step explanation:
