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mamaluj [8]
4 years ago
5

Solve x^2-3x-20=8 for quadratic equation​

Mathematics
2 answers:
lesya692 [45]4 years ago
4 0

We have

x^2-3x-20=8

First, move 8 to left side to get

x^2-3x-28=0

Rewrite x^2-3x-28 as (x-7)(x+4) to get

(x-7)(x+4)=0

The expression on the left equals zero if either of factors is zero thus the equation has 2 solutions

x-7=0\Longrightarrow\boxed{x_1=7}

x+4=0\Longrightarrow\boxed{x_2=-4}

Hope this helps.

snow_lady [41]4 years ago
3 0

Answer:

x = -7

x = 4

Step-by-step explanation:

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