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NISA [10]
3 years ago
7

At a candy store, Erika bought 3 kilograms of cinnamon red hots and 1 kilogram of gummy bears for $21.00. Meanwhile, Irene bough

t 3 kilograms of cinnamon red hots and 3 kilograms of gummy bears for $39.00. What is the cost of one kilogram of each type of candy?
Mathematics
1 answer:
sattari [20]3 years ago
8 0
Taking the difference of the both you can see that 2 kg of gummy bears would cost $18. So each kg of gummy bear is $9. Now subtract $9 from what Erika bought, and 3 kg of red hots are $12. So each kg of red hots are $4.
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If X and Y vary directly, as x decreases, what happens to the value of y?
diamong [38]
As x decreases y also decreased
5 0
3 years ago
Value discounting refers to the fact that the percieved value of the reinforcer is less the longer you have to wait for it. See
vekshin1

Answer:

there is an economic principle that states that 1 dollar today is worth more than 1 dollar in the future, since an invested dollar could earn interests and gain value.

For example, we can assume a 6% interest rate (0.5% monthly interest rate), and using the present value formula we can determine the present value of $100:

  • given to us in 30 days = $100 / (1 + 0.5%)¹ = $99.50
  • given to us in 150 days = $100 / (1 + 0.5%)⁵ = $97.54
  • given to us in 300 days = $100 / (1 + 0.5%)¹⁰ = $95.13

In order to calculate the value of $100 given to us tomorrow, we would need to determine a daily interest rate = 6% / 360 = 0.00017

  • $100 given to us tomorrow = $100 / (1 + 0.00017)¹ = $99.98

since the amount of money is not that large and the interest rate is rather low, the difference in value is not that large. But imagine if you used a 24% interest rate instead of 6% (monthly interest rate = 2%)

  • $100 given to us in 30 days = $100 / (1 + 2%)¹ = $98.04
  • $100 given to us in 150 days = $100 / (1 + 2%)⁵ = $90.57
  • $100 given to us in 300 days = $100 / (1 + 2%)¹⁰ = $82.03

as the interest rate increases, the present value decreases.

5 0
3 years ago
Please someone help me to prove this. ​
dem82 [27]
<h3><u>Answer</u> :</h3>

We know that,

\dag\bf\:sin^2A=\dfrac{1-cos2A}{2}

\dag\bf\:sin2A=2sinA\:cosA

<u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u>

<u>Now, Let's solve</u> !

\leadsto\:\bf\dfrac{sin^2A-sin^2B}{sinA\:cosA-sinB\:cosB}

\leadsto\:\sf\dfrac{\frac{1-cos2A}{2}-\frac{1-cos2B}{2}}{\frac{2sinA\:cosA}{2}-\frac{2sinB\:cosB}{2}}

\leadsto\:\sf\dfrac{1-cos2A-1+cos2B}{sin2A-sin2B}

\leadsto\:\sf\dfrac{2sin\frac{2A+2B}{2}\:sin\frac{2A-2B}{2}}{2sin\frac{2A-2B}{2}\:cos\frac{2A+2B}{2}}

\leadsto\:\sf\dfrac{sin(A+B)}{cos(A+B)}

\leadsto\:\bf{tan(A+B)}

5 0
3 years ago
Read 2 more answers
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11Alexandr11 [23.1K]

Answer:

Quotient: x^(2)-6

Reminder: 7

Step-by-step explanation:

See the attached image.

8 0
3 years ago
The hypothesis of a statement is the if part.<br><br> Always<br> Sometimes<br> Never
Mashutka [201]
Sometimes; though your question isn't that clear.
8 0
3 years ago
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