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anygoal [31]
3 years ago
12

Which of the following is not a valid representation of a probability? Group of answer choices 0 3/8 35% 1.04

Mathematics
1 answer:
Jlenok [28]3 years ago
6 0

Answer:

0

Step-by-step explanation:

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Kate, Alexia, and Trina just completed the 400-meter dash at the track meet. Kate finished the race 6 seconds faster than Alexia
Digiron [165]

Answer:

Kate = 52 seconds, Alexia = 58 seconds, Trina = 49 seconds

Step-by-step explanation:

A = K + 6

T = K - 3

K + A + T = 2 min 39 sec or 159 sec

K + (K + 6) + (K - 3) = 159sec

3K + 3 = 159sec

3K = 156sec

K = 52 sec

A = 52 + 6 = 58 sec

T = 52 - 3 = 49 sec

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3 years ago
Evaluate the power
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Answer:

289

Step-by-step explanation:

Raise 17 to the power of 2

Is this what you are asking for

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2 years ago
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Maddie tried to divide 160 stickers equally amongst herself and 5 friends. There was some stickers left over, so she kept them.
Nutka1998 [239]

Answer:

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Step-by-step explanation:

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aev [14]

rylie purchases 5 cans

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3 years ago
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Help needed math 3 - 10 points read closely
inessss [21]
<h2>Hello!</h2>

The answer is:

The answer is the fourth option,

f(-3)=-\frac{1}{3}

<h2>Why?</h2>

Piecewise functions are functions that are composed by two or more expressions, the expression to use will depend of the domain or input that we need to evaluate.

We are given the piecewise function:

\left \{ {{\frac{1}{x}, if x

There, we know that:

We should use the first expression if the value to evaluate is less than -2.

So, for this case, the function will be:

f(x)=\frac{1}{x}

We should use the second expression if the value to evaluate is greater or equal than 2.

So, for this case, the function will be:

f(x)=x^{2}

Now, since we are given that the value to evaluate is -3, and its less than -2, we need to use the first expression, and evaluate it.

-3

So, evaluating the function we have:

f(x)=\frac{1}{x}

f(-3)=\frac{1}{-3}

f(-3)=-\frac{1}{3}

Hence, we have that the answer is the fourth option,

f(-3)=-\frac{1}{3}

Have a nice day!

7 0
3 years ago
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