Answer:
H=9;8)
B=(5;4) (ball)
R=(7;0) (hit point)
B'=symetric of B axis perpendicular of x in R
B'=(7+(7-5);4)=(9;4)
Equation BR: y-4=(0-4)/(7-5)(x-5)==>y=-2x+14
Equation RB': y-4=(4-0)/(9-7)(x-9)==>y=2x-14
Is H a point of RB'? y=2x-14 : 8=? 2*9-14==>8=?4 No!
you will not make your putt
Step-by-step explanation:
The Real Answer is B: Leasing a car for a certain period.
Hope this helps!
Answer:
y = 3
Step-by-step explanation:
Let's start with the left side of the equation.
5(y-2)-2= 2(y+1)-5
5y-10-2= 2(y+1)-5
Now let's solve the right side
5y-10-2= 2y+2-5
5y-12= 2y-3
-2y -2y
3y-12=-3
+12 +12
3y = 9
3y/3 = 9/3
y = 3
hope this helps!
we are given with an isosceles triangle with two congruent sides equal to 70 inches and an angle of 36 degrees in between the sides. We are asked for the area of the triangle. The formula is A = 0.5 * ab sin theta where a and b are the sides. The area is equal to 1440. 07 in2.
Answer:
it would be the first one 16
