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Ghella [55]
3 years ago
7

A ball is thrown into the air at an initial velocity of 18 meters per second from an initial height of 10 meters. The equation t

hat models the path of the ball is given by h=-4.9t^2+18t+10h How high is the ball at 3 seconds?
Group of answer choices

19.9 meters

108.1 meters

10 meters

The ball is no longer in the air at 3 seconds.
Mathematics
1 answer:
Sergio039 [100]3 years ago
7 0

Answer:

Step-by-step explanation:

This is your position equation:

s(t)=-4.9t^2+18t+10

There's a whole lot of information in that equation, but what we are concerned about right now is the height of the ball after t = 3 seconds.  If this is the position of the ball at any time t, we will sub in 3 for t to find out where the ball is at 3 seconds.

s(3)=-4.9(3^2)+18(3)+10

which simplifies to

s(3) = -44.1 + 54 + 10 which is

s(3) = 19.9 meters

That's how high the ball is in the air at 3 seconds.

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