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4 years ago

What answer to 7(v+9)-8(5-7)

Mathematics

2 answers:

ratelena [41]4 years ago

8 0

Distribute 7 to (v + 9) using PEMDAS, and use PEMDAS to solve -8(5-7).

7(v + 9) = 7v + 63

(5 - 7) = -2(-8) = 16

7v + 63 + 16

Simplify. Combine like terms

7v + 79

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7v + 79 is your answer

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hope this helps

postnew [5]4 years ago

7 0

Hope this helps u...!!

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Which equation shows a line perpendicular to the line

LenaWriter [7]

Answer:

The second answer: y= 3/4x + 2

Step-by-step explanation:

Subtract 4x to the other side

Divide by 3 to get y by itself

Make the coefficient of the x term the negative reciprocal, for that is the perpendicular slope of the line

3 0

3 years ago

Simplify the radical expression. √45 + √20 - √5

viva [34]

√45 = √9√5 = 3√5
√20 = √4√5 = 2√5

3√5+2√5-√5=4√5

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:)

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3 years ago

Help please due soon

mestny [16]

The think the answer is c

7 0

3 years ago

Image point B (4,-8) was transformed using the translation (x-2,y+3) what were the coordinates of B?

PilotLPTM [1.2K]

The coordinates of the image point are given to be B(4, -8). We are to find the coordinates of pre-image that is the coordinates before the translation.

The translation made was (x-2, y+3)

This means, the x coordinate was moved 2 units to left and y coordinate was moved 3 units above.

So, the coordinates of original point will be, 2 units to right of B and 3 units down of B.

So the coordinates will be (6, -11)

5 0

3 years ago

Read 2 more answers

Again ... Commute times in the U.S. are heavily skewed to the right. We select a random sample of 500 people from the 2000 U.S.

VladimirAG [237]

Answer:

We conclude that the mean commute time in the U.S. is less than half an hour.

Step-by-step explanation:

We are given that a random sample of 500 people from the 2000 U.S. Census is selected who reported a non-zero commute time.

In this sample the mean commute time is 27.6 minutes with a standard deviation of 19.6 minutes.

Let $\mu$ = mean commute time in the U.S..

So, Null Hypothesis, $H_0$ : $\mu \geq$ 30 minutes {means that the mean commute time in the U.S. is more than or equal to half an hour}

Alternate Hypothesis, $H_A$ : $\mu$ < 30 minutes {means that the mean commute time in the U.S. is less than half an hour}

The test statistics that would be used here One-sample t-test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean commute time = 27.6 minutes

s = sample standard deviation = 19.6 minutes

n = sample of people from the 2000 U.S. Census = 500

So, the test statistics = $\frac{27.6 -30}{\frac{19.6}{\sqrt{500} } }$ ~ $t_4_9_9$

= -2.738

The value of t test statistic is -2.738.

Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the t table gives critical values of -1.645 at 499 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of t as -2.378 < -1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean commute time in the U.S. is less than half an hour.

4 0

4 years ago