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PIT_PIT [208]
3 years ago
5

The composite figure is made up of a triangle, a square, and a trapezoid. Find the area.

Mathematics
2 answers:
swat323 years ago
8 0

Answer:

Step-by-step explanation:

vredina [299]3 years ago
3 0

Answer by JKismyhusbandbae: The answer is 49.

You wanna calculate the triangle and trapezoid and the square separately and add all the them together.

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Find the solution(s) to the equation sin(x/2) + cos x - 1 = 0 on the interval 0 less than or equal to x 2pie
quester [9]

Answer:

A: 0

B: pi/3

E: 5pi/3

Step-by-step explanation:

8 0
3 years ago
Celeste uses 24 inches of ribbon from a spool that holds 36 inches of ribbon. Which shows equivalent representations for the par
never [62]
Your simplified answer is indeed 2/3 (or 60%, or 0.6) because the fraction 24/36 can be simplified by dividing both the numerator and denominator by 6, which leaves you with 2/3.
3 0
4 years ago
Whenever the population standard deviation is unknown, which distribution is used in developing an interval estimate for a popul
r-ruslan [8.4K]

Answer:

The t-distribution is used.

Step-by-step explanation:

When we dont know the standard deviation of the population, we use the t-distribution(t-table).

Otherwise, the z-distribution(z-table) is used.

So the answer to this question is the t-distribution.

4 0
3 years ago
Which is the simplified form of r^-7 + s^-12
makkiz [27]

Answer:

The simplified form of r^-7 + s^-12 is ----> 1/r^7 + 1/s^12

Step-by-step explanation:

3 0
3 years ago
20% of US High School teens vape. A local High School has implemented campaigns to reduce vaping among students and believes tha
zaharov [31]

Answer:

10.93% probability of observing 51 or fewer vapers in a random sample of 300

Step-by-step explanation:

I am going to use the normal approximation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 300, p = 0.2

So

\mu = E(X) = np = 300*0.2 = 60

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{300*0.2*0.8} = 6.9282

What is the approximate probability of observing 51 or fewer vapers in a random sample of 300?

Using continuity corrections, this is P(X \leq 51 + 0.5) = P(X \leq 51.5), which is the pvalue of Z when X = 51.5 So

Z = \frac{X - \mu}{\sigma}

Z = \frac{51.5 - 60}{6.9282}

Z = -1.23

Z = -1.23 has a pvalue of 0.1093.

10.93% probability of observing 51 or fewer vapers in a random sample of 300

4 0
3 years ago
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