In the circle O is the centre and PB and PA are tangents

Mathematics

1 answer:

xz_007 [3.2K]3 years ago

8 0

Answer:

Angle BCA (48 degrees) is an inscribed angle and the arc it intercepts (arc AB) is twice the inscribed angle. So arc AB is 96 degrees.

Angle AOB is a central angle and angle BPA consists of 2 tangents.

When a central angle (2 radii) intersects with 2 tangents, the 2 angles formed sum to 180 degrees. (Angle BOA + Angle BPA = 180 degrees).

Angle BOA = arc AB = 96 degrees.

Angle BOA + angle APB = 180

Therefore, Angle APB = 84 degrees.

Step-by-step explanation:

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