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Aneli [31]
3 years ago
15

What is the first step in writing f(x) = 3x2 + 6x – 8 in vertex form?

Mathematics
2 answers:
DedPeter [7]3 years ago
7 0

Answer:

Factor out 3 from the first two terms.

Step-by-step explanation:

kkurt [141]3 years ago
5 0
The first step in writing f(x) = 3x² + 6x - 8 in vertex form is

E. Factor out 3 from the first two terms.

f(x) = 3x² + 6x - 8
f(x) = 3(x² + 2x) - 8
f(x) + 8 = 3(x² + 2x + __)
f(x) + 8 + 1 = 3(x² + 2x + 1)
f(x) + 9 = 3(x+1)²
f(x) = 3(x+1)² - 9

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A national grocery store chain wants to test the difference in the average weight of turkeys sold in Detroit and the average wei
Arte-miy333 [17]

Answer:

<em>Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom</em>

<em>The null hypothesis is accepted . </em>

<em>Assume the population variances are approximately the same</em>

<u><em>Step-by-step explanation:</em></u>

<u>Explanation</u>:-

Given data a random sample of 20 turkeys sold at the chain's stores in Detroit yielded a sample mean of 17.53 pounds, with a sample standard deviation of 3.2 pounds

<em>The first sample size  'n₁'= 20</em>

<em>mean of the first sample 'x₁⁻'= 17.53 pounds</em>

<em>standard deviation of first sample  S₁ = 3.2 pounds</em>

Given data a random sample of 24 turkeys sold at the chain's stores in Charlotte yielded a sample mean of 14.89 pounds, with a sample standard deviation of 2.7 pounds

<em>The second sample size  n₂ = 24</em>

<em>mean of the second sample  "x₂⁻"= 14.89 pounds</em>

<em>standard deviation of second sample  S₂ =  2.7 poun</em>ds

<u><em>Null hypothesis</em></u><u>:-</u><u><em>H₀</em></u><em>: The Population Variance are approximately same</em>

<u><em>Alternatively hypothesis</em></u><em>: H₁:The Population Variance are approximately same</em>

<em>Level of significance ∝ =0.05</em>

<em>Degrees of freedom ν = n₁ +n₂ -2 =20+24-2 = 42</em>

<em>Test statistic :-</em>

<em>    </em>t = \frac{x^{-} _{1} -  x_{2} }{\sqrt{S^2(\frac{1}{n_{1} } }+\frac{1}{n_{2} }  }

<em>    where         </em>S^{2}   = \frac{n_{1} S_{1} ^{2}+n_{2}S_{2} ^{2}   }{n_{1} +n_{2} -2}

                      S^{2} = \frac{20X(3.2)^2+24X(2.7)^2}{20+24-2}

<em>              substitute values and we get  S² =  40.988</em>

<em>     </em>t= \frac{17.53-14.89 }{\sqrt{40.988(\frac{1}{20} }+\frac{1}{24}  )}<em></em>

<em>  </em>   t =  1.3622

  Calculated value t = 1.3622

Tabulated value 't' =  2.081

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

<u><em>Conclusion</em></u>:-

<em>The null hypothesis is accepted </em>

<em>Assume the population variances are approximately the same.</em>

<em>      </em>

<em>                        </em>

<em>                    </em>

6 0
2 years ago
Suppose that you draw two cards from a deck. After drawing the first card, you do not put the first card back in the deck. What
AVprozaik [17]

Answer:

The correct answer is 0.05882.

Step-by-step explanation:

A deck of cards have 52 cards, 13 cards of each suit.

We are drawing two cards without replacement.

We need to find the probability of getting a diamond as the first card.

Favorable outcomes are 13 and total number of outcomes are 52.

Thus this probability is \frac{13}{52} = \frac{1}{4}.

Now for the next draw we again want to pick a diamond card.

Favorable outcomes are 12 and total number of leftover cards are 51.

Thus this probability is \frac{12}{51}.

Now the probability that both cards are diamonds is \frac{1}{4} × \frac{12}{51} = \frac{3}{51} = \frac{1}{17} = 0.0588235 ≈ 0.05882

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Answer:11

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