Ask question

Ask question

All categories

2 years ago

7

How is everyone's day

1 answer:

weqwewe [10]2 years ago

8 0

Answer:

Mine's going good. Just doing school at home and playing volleyball

You might be interested in

Please help <br> The diagram shows a 5ft student standing near a tree

Novosadov [1.4K]

Answer:

25 ft

Step-by-step explanation:

The diagram shows two triangles that are similar. Similar triangles have equal angles and sides that are proportional to each other. Since the base of each triangle is given, we can find the proportion of the sides:

$\frac{smaller}{larger}=\frac{8}{40}=\frac{1}{5}$

Given the ratio of the smaller to larger triangle, we can set up a proportion to find the missing height of the larger triangle:

$\frac{1}{5}=\frac{5}{x}$ , where 'x' represent the height of the tree

cross-multiply: x = (5)(5) or 25 ft

8 0

3 years ago

What integer values for a and b would make the following statement true?

Shalnov [3]

Answer:

i think the values for a and b are: a=2 and b=1/4

3 0

2 years ago

Solve the equation. Check the solution -4/x+1 = -1/x+5

boyakko [2]

The answer to this equation is x= -19/3

4 0

3 years ago

Read 2 more answers

Find three positive numbers whose sum is 140 and whose product is a maximum. (Enter your answers as a comma-separated list.)

Paladinen [302]

Answer:

$\frac{140}{3}, \frac{140}{3}, \frac{140}{3}$

Step-by-step explanation:

Let the numbers be $x, y\ and\ z.$

Such that:

$x + y + z = 140$

Make z the subject

$z = 140 -x - y$

For their product to be maximum, we have:

$f(x,y,z) = xyz$

Substitute $z = 140 -x - y$ in $f(x,y,z) = xyz$

$f(x,y) = xy(140 - x - y)$

Open bracket

$f(x,y) = 140xy - x^2y - xy^2$

Differentiate w.r.t x and y

$f_x=140y - 2xy - y^2$

$f_y=140x - x^2 - 2xy$

Since the products are maximum, then $f_x = f_y = 0$

For $f_x=140y - 2xy - y^2$

$140y - 2xy - y^2 = 0$

Factorize:

$y(140 - 2x - y) = 0$

Split

$y = 0\ or\ 140 - 2x - y = 0$

Make y the subject

$y = 0\ or\ y = 140 - 2x$

For $f_y=140x - x^2 - 2xy$

$140x - x^2 - 2xy = 0$

---------------------------------------------------

Substitute y = 0

$140x - x^2 -2x*0 = 0$

$140x - x^2 = 0$

Factorize

$x(140 - x)= 0$

$x = 0\ or\ 140-x = 0$

$x = 0\ or\ x = 140$

---------------------------------------------------

Substitute $y = 140 - 2x$

$140x - x^2 - 2xy = 0$

$140x - x^2 - 2x(140 - 2x) = 0$

$140x - x^2 - 280x + 4x^2 = 0$

Re-arrange

$4x^2 -x^2 +140x - 280x = 0$

$3x^2 -140x = 0$

Factor x out

$x(3x - 140) = 0$

Divide through by x

$3x - 140 = 0$

$3x = 140$

$x = \frac{140}{3}$

Recall that: $y = 140 - 2x$

$y = 140 - 2 * \frac{140}{3}$

$y = 140 - \frac{280}{3}$

Take LCM

$y = \frac{140*3-280}{3}$

$y = \frac{140}{3}$

Recall that:

$z = 140 -x - y$

$z = 140 - \frac{140}{3} - \frac{140}{3}$

Take LCM

$z = \frac{3 * 140- 140 - 140}{3}$

$z = \frac{140}{3}$

Hence, the numbers are:

$\frac{140}{3}, \frac{140}{3}, \frac{140}{3}$

8 0

2 years ago

Which graph represents the function below?

Nady [450]

Answer=last one

Good luck

4 0

2 years ago