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2 years ago

Which is greatest to least 1.001, 1.1,1.403, 1.078

Mathematics

2 answers:

Marat540 [252]2 years ago

8 0

1.403, 1.078 , 1.078 , 1.001, 1.1

Viktor [21]2 years ago

4 0

1) 1.403

2) 1.1

3) 1.078

4) 1.001

HOPE THIS HELPED :)

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M is the midpoint of CD. Given the coordinates of one endpoint C(10,-5) and the midpoint M(4, 0), find the coordinates of the ot

mash [69]

Answer:

D(-2, 5).

Step-by-step explanation:

We are given that M is the midpoint of CD and that C = (10, -5) and M = (4, 0).

And we want to determine the coordinates of D.

Recall that the midpoint is given by:

$\displaystyle M = \left(\frac{x_1 + x_2}{2} , \frac{y_1 + y_2}{2}\right)$

Let C(10, -5) be (x₁, y₁) and Point D be (x₂, y₂). The midpoint M is (4, 0). Hence:

$\displaystyle (4, 0) = \left(\frac{10+x_2}{2} , \frac{-5+y_2}{2}\right)$

This yields two equations:

$\displaystyle \frac{x_2 + 10}{2} = 4\text{ and } \frac{y_2 - 5}{2} = 0$

Solve for each:

$\displaystyle \begin{aligned}x_2 + 10 &= 8 \\ x_2 &= -2 \end{aligned}$

And:

$\displaystyle \begin{aligned} y_2 -5 &= 0 \\ y_2 &= 5\end{aligned}$

In conclusion, Point D = (-2, 5).

5 0

2 years ago

Find the volume to the nearest cm3 20 cm 35 cm 12 cm

riadik2000 [5.3K]

Answer: 10380cm^3

Explanation:

Find the volume of half cylinder:

V = (pi x r^2 x h)/2 (I use pi = 22/7 for simplifying)
V = 22/7 x 6^2/2 x 35
V = 22/7 x 36/2 x 35
V = 22/7 x 35 x 18
V = 22 x 5 x 18
V = 1980cm^3

Find the volume of the rectangle:

V = 20 x 35 x 12
V = 240 x 5 x 7
V = 1200 x 7
V = 8400cm^3

Find the volume of the whole shape:

V = 1980 + 8400
V = 10380cm^3

3 0

2 years ago

I need help with this question

dsp73

The slope is 9/3 which can be simplified into 3/1

5 0

2 years ago

A stack of logs has 32 logs on the bottom layer. Each subsequent layer has 6 fewer logs than the previous layer. If the top laye

Svetlanka [38]

Answer: The total number of logs in the pile is 6.

Step-by-step explanation: Given that a stack of logs has 32 logs on the bottom layer. Each subsequent layer has 6 fewer logs than the previous layer and the top layer has two logs.

We are to find the total number of logs in the pile.

Let n represents the total number of logs in the pile.

Since each subsequent layer has 6 fewer logs then the previous layer, so the number of logs in each layer will become an ARITHMETIC sequence with

first term, a = 32 and common difference, d = -6.

We know that

the n-th term of an arithmetic sequence with first term a and common difference d is

$a_n=a+(n-10)d.$

Since there are n logs in the pile, so we get

$a+(n-1)d=2\\\\\Rightarrow 32+(n-1)(-6)=2\\\\\Rightarrow 32-6n+6=2\\\\\Rightarrow 6n=36\\\\\Rightarrow n=6.$

Thus, the total number of logs in the pile is 6.

6 0

2 years ago

Substitution method need help for home work

Marizza181 [45]

-3y = x...so we sub in -3y for x in the other equation

-x + 7y = 70
-(-3y) + 7y = 70
3y + 7y = 70
10y = 70
y = 70/10
y = 7

so we sub in 7 for y in either of the original equations to find x
-3y = x
-3(7) = x
-21 = x

so ur solution is (-21,7)

6 0

2 years ago