Answer:
68.11% probability that the firm involved is firm B
Step-by-step explanation:
Bayes Theorem:
Two events, A and B.

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.
In this question:
Event A: Cost overrun
Event B: Agency B used.
A certain federal agency employs three consulting firms (A, B and C) with probabilities 0.40, 0.45 and 0.15.
This means that 
From past experiences, it is known that the probability of cost overruns for the firms are 0.01, 0.14, and 0.17, respectively.
This means that 
Probability of cost overrun.
Firm A is used 40% of the time, with 1% of these having cost overrun. B is used 45%, with 14% of these having cost overruns. C is used 15% of the time, with 17% of these having cost overruns.
So

What is the probability that the firm involved is firm B

68.11% probability that the firm involved is firm B
Answer:
219 games.
Step-by-step explanation:
Given the following data;
Cost of each game = $3
Cost of award = $150
Let x = number of games played.
Translating the word problem into an algebraic equation, we have;
<em>Rearranging the equation, we have;</em>
<em>Dividing both sides by 3, we have;</em>


<em>Therefore, the number of games to be played in order to make $507 is at least 219 games. </em>
Gauss' method for addition relies on the fact that you can 'pair' certain numbers together. Look at the example:
1+2+3+4+5+6+7+8+9+10
We could manually add all these together from left to right but a clever way to think about this is if we add together the ends of the sum (10+1) we get 11. If we then move one in from the ends and add these (2+9) we also get 11. This means that 1+2+...+9+10 is the same as 11+11+...+11+11.
Because each 2 numbers adds to 11 we know the total number of 11's we have to add together is the length of the sum divided by 2. In our case 5 (10 ÷ 2). We need to add 5 lots of 11 to get our answer. This is the same as 11 × 5 which is easily seen to be 55.
(If you add the 10 numbers together on a calculator you'll see 1+2+3+4+5+6+7+8+9+10 = 55) so this method really makes it a lot quicker.
Looking at your sequence, if we pair the ends together we get 401 (400+1) and we multiply this by the length of the sequence divided by 2. In your case, 200 (400 ÷ 2).
So the sum of all the numbers from 1 to 400 must be 401 × 200 = 80,200.
Remember the steps:
1. Pair the ends together and add them
2. Times this number by the length of the sequence halved
Hope this helps.