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2 years ago

1)The sum of two numbers is 43, and their differences is 7. Find the smaller number.

Mathematics

1 answer:

Misha Larkins [42]2 years ago

4 0

so lets start with making these equations

x + y = 43

x - y = 7

now we can rewrite the second equation in terms of x

x = 7 + y

now we plug that x value back into the first equation

7 + y + y = 43

7 + 2y = 43

2y = 36

y = 18

now we can plug the value of y into the rewritten second equation leaving us with

x = 7 + 18

x = 25

so y = 18 and x = 25

and the difference is 7

please give brainliest!

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Please solve the problem.

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OK. I did it, and I have the solution.
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   (5 + 2x) · (4 + 2x) .

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and the question tells us that the area of the whole big rectangle is 90 yds² .
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   4x² + 18x + 20 = 90 .

Subtract 90 from each side:    4x² + 18x - 70 = 0
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Use the distributive property to write an expression equivalent to 5 times(3 plus 4)

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5x(3+4) = (5x3)+(5x4)

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Paraphin [41]

The area of a shape is the amount of space a shape can occupy, while the perimeter is the sum of its lengths.

The perimeter is $18 + 3\sqrt 5 + 3\sqrt 2$ units
The area of the sanctuary is 27 square units

We have:

$A = (5,7)\\B=(8, 7)\\C=(8, 1)\\D=( 1, 1)\\E=( 1, 4)\\F= ( 5,4)$

Perimeter

See attachment for the layout of the sanctuary

$BC = \sqrt{(8 - 8)^2 + (7 - 1)^2} = 6$

$EF = \sqrt{(1 - 5)^2 + (4 - 4)^2} = 4$

$FA = \sqrt{(5 - 5)^2 + (4 - 7)^2} = 3$

From the attachment, the sides are

AB, BF, FC, CD, DE and EA

Start by calculating the length of each side using the following distance formula:

$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_2)^2}$

So, we have:

$AB = \sqrt{(5 - 8)^2 + (7 - 7)^2} = 3$

$BF = \sqrt{(8 - 5)^2 + (7 -1)^2} = \sqrt{45} = 3\sqrt 5$

$FC = \sqrt{(8 - 5)^2 + (1 -4)^2} = \sqrt{18} = 3\sqrt 2$

$CD = \sqrt{(8 - 1)^2 + (1 - 1)^2} = 7$

$DE = \sqrt{(1 - 1)^2 + (1 - 4)^2} = 3$

$EA = \sqrt{(1 - 5)^2 + (4 -7)^2} = 5$

So, the perimeter (P) is:

$P = AB + BF + FC + CD + DE + EA$

$P = 3 + 3\sqrt 5 + 3\sqrt 2 + 7 + 3 + 5$

$P = 18 + 3\sqrt 5 + 3\sqrt 2$

Hence, the perimeter is $18 + 3\sqrt 5 + 3\sqrt 2$ units

Area

To calculate the area, we need to divide the sanctuary into three.

Triangle ABF
Triangle EFA
Trapezium CDEF

The area of ABF is:

$Area = \frac 12 \times AB \times FA$

Where:

$AB = 3$

$FA = \sqrt{(5 - 5)^2 + (4 - 7)^2} = 3$

$Area = \frac 12 \times 3 \times 3$

$Area = \frac 92$

The area of EFA is:

$Area = \frac 12 \times EF \times FA$

Where:

$FA = 3$

$EF = \sqrt{(1 - 5)^2 + (4 - 4)^2} = 4$

So:

$Area = \frac 12 \times 4 \times 3$

$Area = 6$

The area of CDEF is:

$Area = \frac 12(CD + EF) \times DE$

Where

$CD = 7$

$EF = 4$

$DE = 3$

So, we have:

$Area = \frac 12 (7 + 4) \times 3$

$Area = \frac 12 \times 11 \times 3$

$Area = \frac {33}2$

So, the area of the sanctuary is:

$Area = \frac 92 + 6 + \frac {33}2$

$Area = \frac {9 +12 + 33}2$

$Area = \frac {54}2$

$Area = 27$

Hence, the area of the sanctuary is 27 square units

Read more about areas and perimeters at:

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