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2 years ago

Find each percent of the markup. $11.5 marked up to $25. Round to the nearest percent.

1 answer:

8 0

Percent markup=amountmarkedup/original times 100

amountmarkedup=25-13.5.5=11.5
original=13.5

percent markup=11.5/13.5 times 100=0.85 times 100=85% markup

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I really need help pleaseee

Dmitriy789 [7]

Answer:

P=163,487,500

Step-by-step explanation: P=Ae^(kt)

151000000=145000000*e^(k5)

151000000/14500000=e^(k5)

1.04137931=e^(k5)

Ln 1.04=Ln e^(k5)

0.04=k5

k= 0.008

P=145,000,000*e^(.008*15)

P=145,000,000*e^0.12

e=2.71828

P=145,000,000*1.12749685

p=163,487,500

6 0

2 years ago

A shop has a sale that offers 20% off all prices.

NeTakaya

I think that the answer is 45% because the sale started off with a 20% discount, but at the end they added another 25% to the sales. So since the sale already started off with 20%, you add 20%+25% which equals 45%.

5 0

2 years ago

Do this for me pls its mdths

Vadim26 [7]

Answer:

A = -1

B = -3

C = -7

Step-by-step explanation:

See attached image.

5 0

1 year ago

AM= 5x+10 MB= 4x+16 is the midpoint of AM. Find AM

Lady bird [3.3K]

5x+10=4x+16
x=6
AM= 40

6 0

2 years ago

What is [(7x^3)(y^2)]^2/7 in radical form?

GuDViN [60]

Remember
$x^ \frac{m}{n} = \sqrt[n]{x^m}$
and
$(zy)^m=(z^m)(y^m)$
and
(x^m)^n=x^(mn)

so
$((7x^3)(y^2))^ \frac{2}{7} = \sqrt[7]{((7x^3)(y^2))^2}$ =
$\sqrt[7]{((7x^3)^2(y^2)^2)}$ =
$\sqrt[7]{((7^2x^6)(y^4))}$ =
$\sqrt[7]{((49x^6)(y^4))}$ =
$\sqrt[7]{49x^6y^4}$

8 0

2 years ago