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3 years ago

PLZ HELP ASAP WILL GIVE BRAINLIEST!!!!!!!!

Mathematics

1 answer:

docker41 [41]3 years ago

8 0

I think it's different by
Group 2 has a 1 yet group 2 didn't sorry if wrong

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An item costs $440 before tax, and the sales tax is $30.80.

JulsSmile [24]

Answer:

Step-by-step explanation:

30.80%=0.308

0.308/440=0.0007%

0.0007 is the same as 7%

4 0

3 years ago

Translate the statement into an equation: the difference of four times a number and eight is equal to twenty-three less than tha

neonofarm [45]

Let, the number be "x"
Now,
according to the question,
4x -8 = x -23....................This is your equation.

Now solving it,
4x - 8 = x - 23
4x - x = -23 + 8
3x = -15
x = -15 / 3
x = -5

Checking the answer,
4 (-5) - 8 = (-5) - 23
-20 - 8 = -5 - 23
-28 = -28......................................true

6 0

3 years ago

Read 2 more answers

I need help is it A B C or D

kow [346]

I think its answer A

4 0

4 years ago

PLS HELP

Westkost [7]

Answer:

B and D

Step-by-step explanation:

I don't have much of an explanation, but I remember from taking geometry that those two angles are the same measurement because they're congruent interior angles. hope this helps :)

5 0

3 years ago

A drawer contains 3 white shirts, 2 blue shirts, and 5 gray shirts. A shirt is randomly

shutvik [7]

Answer:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = $\frac{1}{4}$

Step-by-step explanation:

Given that

3 white, 2 blue and 5 gray shirts are there.

To find:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = ?

Solution:

Here, total number of shirts = 3+2+5 = 10

First of all, let us learn about the formula of an event E:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(First\ White) = \dfrac{\text{Number of white shirts}}{\text {Total number of shirts left}}$

$P(First\ White) = \dfrac{3}{10}$

Now, this shirt is set aside.

So, total number of shirts left are 9 now.

$P(First\ White\ and\ second\ gray) = P(First White) \times P(Second\ Gray)\\\Rightarrow P(First\ White\ and\ second\ gray) = P(First White) \times \dfrac{\text{Number of gray shirts}}{\text{Total number of shirts left}}\\\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{3}{10} \times \dfrac{5}{9}\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{1}{2} \times \dfrac{1}{2}\\\Rightarrow P(First\ White\ and\ second\ gray) = \bold{\dfrac{1}{4} }$

So, the answer is:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = $\frac{1}{4}$

4 0

3 years ago