2/8 is the answer because if you do 3-1 it would equal 2 and then you would put 2 over eight. You can even simplify it to 1/4 because 2 and 8 can both be divided by 2.
Answer:
![[11.5-(2.5*3)]^2=16](https://tex.z-dn.net/?f=%5B11.5-%282.5%2A3%29%5D%5E2%3D16)
Step-by-step explanation:
We want to evaluate ![[11.5-(2.5*3)]^2](https://tex.z-dn.net/?f=%5B11.5-%282.5%2A3%29%5D%5E2)
Let us evaluate within the parenthesis first:
![[11.5-(2.5*3)]^2=[11.5-(7.5)]^2](https://tex.z-dn.net/?f=%5B11.5-%282.5%2A3%29%5D%5E2%3D%5B11.5-%287.5%29%5D%5E2)
![\implies [11.5-(2.5*3)]^2=[11.5-7.5]^2](https://tex.z-dn.net/?f=%5Cimplies%20%5B11.5-%282.5%2A3%29%5D%5E2%3D%5B11.5-7.5%5D%5E2)
We again subtract within the bracket to obtain:
![[11.5-(2.5*3)]^2=[4]^2](https://tex.z-dn.net/?f=%5B11.5-%282.5%2A3%29%5D%5E2%3D%5B4%5D%5E2)
This finally gives us:
![[11.5-(2.5*3)]^2=16](https://tex.z-dn.net/?f=%5B11.5-%282.5%2A3%29%5D%5E2%3D16)
Answer:
5/3
Step-by-step explanation:
9514 1404 393
Answer:
y -2 = -2/3(x +4)
Step-by-step explanation:
There are several different forms of the equation for a line. Each is useful in its own way. Here, the line crosses the y-axis at a point between integer values, so using that intercept point could be problematical. That suggests the "point-slope" form of the equation for a line would be a better choice.
That form is ...
y -k = m(x -h) . . . . . . . line with slope m through point (h, k)
__
The two marked points are (-4, 2) and (5, -4). All we need is the slope.
The slope is given by the formula ...
m = (y2 -y1)/(x2 -x1) . . . . . . . . where the given points are (x1, y1) and (x2, y2)
m = (-4 -2)/(5 -(-4)) = -6/9 = -2/3
Using the first point, the equation for the line can now be written as ...
y -2 = -2/3(x -(-4))
y -2 = -2/3(x +4)
Answer:
5m + 4p
Step-by-step explanation: