1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dimas [21]
2 years ago
11

PLZ HELP ASAP WILL GIVE BRAINLIEST!!!!!!!!

Mathematics
1 answer:
docker41 [41]2 years ago
8 0
I think it's different by
Group 2 has a 1 yet group 2 didn't sorry if wrong
You might be interested in
PLZ ANSWER THIS. I really need help from smart people.
r-ruslan [8.4K]

Answer:

2x-3y<7

Step-by-step explanation:

Hope it helps (:

4 0
2 years ago
Karen received a $80 gift card for a coffee store. She used it in buying some coffee that cost $8.23 per pound. After buying the
aleksandrvk [35]

Answer:

4

Step-by-step explanation:

80 - 47.08 = 32.92

32.92/8.23 = 4

4 0
2 years ago
Read 2 more answers
Joey is standing on a diving board that is 5.6 feet above sea level. Joey dives into the water to a depth of -8.6 feet below sea
pashok25 [27]

Answer:

5.6 - (-8.6)

Step-by-step explanation:

6 0
3 years ago
Workers at a certain soda drink factory collected data on the volumes​ (in ounces) of a simple random sample of 1818 cans of the
ohaa [14]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Workers at a certain soda drink factory collected data on the volumes​ (in ounces) of a simple random sample of 18 cans of the soda drink. Those volumes have a mean of 12.19 oz and a standard deviation of 0.14 oz, and they appear to be from a normally distributed population.

If the workers want the filling process to work so that almost all cans have volumes between 12.02 oz and 12.66 ​oz, the range rule of thumb can be used to estimate that the standard deviation should be less than 0.16 oz. Use the sample data to test the claim that the population of volumes has a standard deviation less than 0.16 oz. Use a 0.01 significance level. Complete parts​ (a) through​ (d) below.

a. Identify the null and alternative hypotheses.  

b. Compute the test statistic.

c. Find the p-value.

d. State the conclusion.

Answer:

Null hypotheses = H₀: σ = 0.16  oz

Alternate hypotheses = H₁: σ < 0.16  oz

Critical value = 6.408

Chi-square value = \chi^2 = 13.016

Reject H₀  Since \chi^2 > Critical value

Reject H₀ Since p-value ≤ α

We have significant evidence at given significance level that the population of volumes has a standard deviation of less than 0.16 oz.

Step-by-step explanation:

Set up hypotheses:

The null hypotheses is that the population of volumes has a standard deviation of 0.16 oz

Null hypotheses = H₀: σ = 0.16  oz

The claim to be tested is that the population of volumes has a standard deviation of less than 0.16 oz

Alternate hypotheses = H₁: σ < 0.16  oz

Determine type of test:

Since the alternate hypothesis states that the population of volumes has a standard deviation of less than 0.16 oz, therefore we will use a lower-tailed chi-square test.

Determine the Critical value:

Given level of significance = 0.01

Since it is a lower-tailed test, the areas given in the chi-square table are the areas to the right of the critical value. To get the areas on the left, subtract it from  one, and then look it up

α = 1 - 0.01 = 0.99

degree of freedom = df = n - 1 = 18 - 1 = 17

The critical value from the chi-square table at α = 0.99 and df = 17 is found to be

Critical value = 6.408

Using an online “chi-square p-value calculator”

The left tail p-value for df = 17 and Critical value = 6.408 is found to be

p-value = 0.01

Set up decision rule:

Reject H₀ If  > Critical value

We reject the Null hypothesis If the calculated chi-square value is more than the critical value.

OR

Reject H₀ If p-value ≤ α

Compute the test statistic:

$ \chi^2 = \frac{(n-1) s^2}{\sigma^2} } $

$ \chi^2 = \frac{(18-1) 0.14^2}{0.16^2} } $

\chi^2 = 13.016

Conclusion:

We reject H₀

Since \chi^2 > Critical value

13.016 > 6.408

Also

p-value ≤ α

0.01 ≤ 0.01

We have significant evidence at given significance level that the population of volumes has a standard deviation of less than 0.16 oz.

5 0
2 years ago
MULTIPLE CHOICE HELP ASAP! Brainliest for correct answer.
N76 [4]

Answer:

An equation of the circle with centre (-2,1) and radius 3 is \mathbf{(x+2)^2+(x-1)^2=9}

Option D is correct.

Step-by-step explanation:

Looking at the figure we get centre of circle C (-2,1) and radius of circle r = 3

The equation of circle is of form: (x-h)^2+(x-k)^2=r^2 where (h,k) is centre and r is radius.

We have centre C (-2,1) so, we have h = -2 and k = 1

We have radius = 3 so, r = 3

Putting values in the equation and finding the required equation:

(x-h)^2+(x-k)^2=r^2\\(x-(-2))^2+(x-1)^2=(3)^2\\(x+2)^2+(x-1)^2=9

So,  an equation of the circle with centre (-2,1) and radius 3 is \mathbf{(x+2)^2+(x-1)^2=9}

Option D is correct.

7 0
2 years ago
Other questions:
  • Are these answers correct? also is there any work to be shown?
    11·1 answer
  • if Raphael counted 40 yellow and white cars and there were 9 times more white cars. how many white cars
    9·1 answer
  • Help plz I’m vvvvv confused
    5·2 answers
  • HELP WITH 20 PLEASE!
    13·1 answer
  • What is the volume of the prism the units are 7m 24m and 21m
    5·1 answer
  • In a 52 card deck, 4 are queens, 4 are jacks, and 4 are kings. if the top card is a king, what's the probability that the second
    6·1 answer
  • The question is : The firehouse is shown in the shape of a composite figure, how many cubic yards of space are in the fire house
    8·1 answer
  • Solve the equation <br><br> 5x-(2x-13)=40
    9·2 answers
  • Please help! I need to tell whether x and y are in a proportional relationship and I need to write an equation that represents t
    9·2 answers
  • A video store specializes in three types of movies: children's, American West, and horror. It's known that:
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!