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3 years ago

What are the discontinuities of the function y= 1500/x

1 answer:

4 0

The discontinuity occurs at x = 0, since that is the only "problem" place in the graph that makes the function undefined. A vertical asymptote exists there. It is nonremoveable.

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A sample of 5 buttons is randomly selected and the following diameters are measured in inches. Give a point estimate for the pop

Helen [10]

Answer:

$s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

But we need to calculate the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_I}{n}$

And replacing we got:

$\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072$

And for the sample variance we have:

$s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003$

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance $\sigma^2$

$E(s^2) = \sigma^2$

Step-by-step explanation:

For this case we have the following data:

1.04,1.00,1.13,1.08,1.11

And in order to estimate the population variance we can use the sample variance formula:

$s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

But we need to calculate the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_I}{n}$

And replacing we got:

$\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072$

And for the sample variance we have:

$s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003$

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance $\sigma^2$

$E(s^2) = \sigma^2$

3 0

3 years ago

James did not get the PlayStation that he wanted for his birthday, but instead, he got $80. He decided that he will save the $80

Vika [28.1K]

W=14 that’s because 360-80=280 then you have to divide that by 20. And you get 14 weeks.

6 0

3 years ago

X and y vary inversely and x=50 when y=5 find y when x=10 what is k?

Kisachek [45]

Answer:

Part A)

1) $k=250$

2) $y=25$

Part B)

1) $k=7$

2) $y=84$

Step-by-step explanation:

Part 1) x and y vary inversely and x=50 when y=5 find y when x=10 what is k?

we know that

A relationship between two variables, x, and y, represent an inverse variation if it can be expressed in the form $y*x=k$ or $y=k/x$

step 1

Find the value of k

x=50 when y=5

substitute the values

$y*x=k$ ------> $5*50=k$ -----> $k=250$

The equation is equal to

$y*x=250$ or $y=250/x$

step 2

Find y when x=10

substitute the value of x in the equation and solve for y

$y*(10)=250$

$y=250/10=25$

Part B) x and y vary directly and x=6 when y=42 find k what is y when x=12

we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form $y/x=k$ or $y=kx$

step 1

Find the value of k

x=6 when y=42

substitute the values

$y/x=k$ ------> $42/6=k$ -----> $k=7$

The equation is equal to

$y/x=7$ or $y=7x$

step 2

Find y when x=12

substitute the value of x in the equation and solve for y

$y=7(12)=84$

5 0

3 years ago

PLEASE HELP ME! 100 POINTS! ;( question 10, 11, 12, 13, 14, 15. I have a f in this class and could use your help a lot! I will l

MatroZZZ [7]

There are a lot of problems here so I'll try to be brief with each one so I don't add a lot of clutter

Problem 10) This is arithmetic because we subtract 6 from each term to get the next. This is the same as adding on -6. The common difference is d = -6. The first term is a = 1

Problem 11) Neither. The distance from 3 to 3/2 = 1.5 is 1.5 units, but the distance from 1.5 to 1 is 0.5 units. This implies there is no common difference value. The sequence is not arithmetic because of this. It's also not geometric either. To go from 3 to 3/2, we multiply by 1/2. But then going from 3/2 to 1, we multiply by 2/3. There is no common ratio r value.

Problem 12) This sequence is geometric. We divide each term by 3 to get the next, or put another way, we multiply each term by 1/3 to get the next term. The common ratio is r = 1/3. The first term is a = 108.

Problem 13) Neither. This is because going from term to term, we do not add the same amount each time. Example: from -2 to 4 we add 6, but then from 4 to -6 we add -10. So the sequence is not arithmetic. It's also not geometric either because we dont multiply by the same term each time. Eg: from -2 to 4, we multiply by -2; but from 4 to -6 we multiply by -1.5

Problem 14) The next three terms are: 1, 1/4, 1/16. This is found by multiplying each term by the common ratio r = 1/4, or you can think of dividing each term by 4. To get this common ratio, pick any term you want and divide it by its previous term. Example: term2/term1 = 16/64 = 1/4 = common ratio.

Problem 15) The next three terms are: -432, 2592, -15552. You multiply each term by the common ratio -6. Like with the previous problem, we divide any term over its previous one to get the common ratio, so for example, term2/term1 = -12/2 = -6 = common ratio.

3 0

3 years ago

A student finished a 30 question test in 75 minutes. Which rate best represents the relationship between the number of minutes s

blagie [28]

Answer:

2.5 minutes per quesiton

Step-by-step explanation:

75 minutes to take 30 quesitons means you divide the time equally so

75/30

5 0

3 years ago