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statuscvo [17]
2 years ago
10

Solve: Tan20. Tan 40. Tan 80plaease help me.....​

Mathematics
1 answer:
earnstyle [38]2 years ago
7 0

Answer: you need more information to solve

Step-by-step explanation:

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Collect like terms<br> x+x+x
Vlad [161]
The correct answer is 3x
3 0
2 years ago
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How many gallons of a 60% antifreeze solution must be mixed with 70 gallons of 20% antifreeze to get a misture that is 50% antif
Komok [63]

Answer:

<h2>210 gaL 60 % Antifreeze II</h2>

Step-by-step explanation:

In the problem, there are two types of antifreeze

antifreeze I and

antifreeze II

antifreeeze I 20 ----70 gal

Antifreeze II 60 ----- x gal

Total 50 ---------------- (70 + x ) gal

20*70+60*x=50(70+x)

1400+60x=3500+50x

60x-50x=3500-1400

10x=2100

x= 210

x=210 gaL 60 % Antifreeze II

4 0
2 years ago
What is 70% of 40,000.
timurjin [86]

Answer:

x = 28,000

Step-by-step explanation:

"What" is our unknown, x; "is" is an equals sign; 70% expressed as a decimal is .70; "of" means to muliply.

Our equation, then, is

x = .70(40,000) so

x = 28,000

5 0
3 years ago
Read 2 more answers
How do you find a vector of length 10 in the direction of vequals=left angle 3 comma negative 2 right angle3,−2​?
Kazeer [188]
First we look for the angle of the vector, which will be given by:
 tan (x) = (- 2/3)
 Clearing x we have:
 x = ATAN (-2/3) = - 33.69 degrees.
 Which means that the angle is 33.69 degrees measured clockwise from the x axis.
 Equivalently the angle is
 360-33.69 = 326.31 degrees
 326.31 degrees measured counterclockwise from the x axis.
 The vector is then:
 v = 10 (cos (326.31) i + sin (326.31) j)
 answer
 v = 10 (cos (326.31) i + sin (326.31) j)
4 0
2 years ago
Find the volume of the solid by rotating the region bounded by y=x^3, y=8, and x=0 about the y axis.
dimulka [17.4K]

Answer:

Solution : Volume = 96/5π

Step-by-step explanation:

If we slice at an arbitrary height y, we get a circular disk with radius x, where x = y^(1/3). So the area of a cross section through y should be:

A(y) = πx^2 = π(y^(1/3))^2 = πy^(2/3)

And now since the solid lies between y = 0, and y = 8, it's volume should be:

V =  ∫⁸₀  A(y)dy (in other words ∫ A(y)dy on the interval [0 to 8])

=> π ∫⁸₀ y^(2/3)dy

=> π[3/5 * y^(5/3)]⁸₀

=> 3/5π(³√8)⁵

=> 3/5π2^5

=> 96/5π ✓

7 0
3 years ago
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