Assume ladder length is 14 ft and that the top end of the ladder is 5 feet above the ground.
Find the distance the bottom of the ladder is from the base of the wall.
Picture a right triangle with hypotenuse 14 feet and that the side opposite the angle is h. Then sin theta = h / 14, or theta = arcsin 5/14. theta is
0.365 radian. Then the dist. of the bot. of the lad. from the base of the wall is
14cos theta = 14cos 0.365 rad = 13.08 feet. This does not seem reasonable; the ladder would fall if it were already that close to the ground.
Ensure that y ou have copied this problem accurately from the original.
Answer:
Not quite sure what you're meant to solve for, but my solution is below.
Step-by-step explanation:
The square root of a value squared is the absolute value of that value, because squaring removes all negatives. Therefore:
Hope this helps!
To do these problems, you plug in the ‘n’ value given into the equation.
a. 6j - 3 : j = 4
6(4) - 3
24 - 3
21
b. 1/2b + 5 : b = 14
1/2(14) + 5
7 + 5
12
c. 8 + 4k : k = 3.5
8 + 4(3.5)
8 + 14
22
Wait doesn’t it tell you how to solve it tho
Answer:
A lies on (1,3) a reflection across the y-axis is (x,y) to (-x,y). The x turns the opposite and y stays the same so...
(-1,3)
