<span>x - 3/(x - 4) + 4 = 3 × x/3
</span>
<span><span>x^2−19/</span><span>x−4</span></span>=x
<span>Step 1: Multiply both sides by x-4.
</span><span><span><span>x^2</span>−19</span>=<span><span>x^2</span>−<span>4x
</span></span></span><span><span><span><span>x^2</span>−19</span>−<span>x^2</span></span>=<span><span><span>x^2</span>−<span>4x</span></span>−<span>x^2</span></span></span><span>(Subtract x^2 from both sides)
</span><span><span>−19</span>=<span>−<span>4x</span></span></span>
<span><span>−<span>4x</span></span>=<span>−19</span></span><span>(Flip the equation)
</span><span><span><span>−<span>4x</span></span><span>/−4</span></span>=<span><span>−19</span><span>/−4 </span></span></span>(Divide both sides by -4)<span>Answer.
x=<span>19/4
</span></span><span>Check answers. (Plug them in to make sure they work.)</span>
Answer:
80
Step-by-step explanation:
the 80 is the tenth part so you do nothing its a trip up qustion
<span>Answer:
Its too long to write here, so I will just state what I did.
I let P=(2ap,ap^2) and Q=(2aq,aq^2)
But x-coordinates of P and Q differ by (2a)
So P=(2ap,ap^2) BUT Q=(2ap - 2a, aq^2)
So Q=(2a(p-1), aq^2)
which means, 2aq = 2a(p-1)
therefore, q=p-1
then I subbed that value of q in aq^2
so Q=(2a(p-1), a(p-1)^2)
and P=(2ap,ap^2)
Using these two values, I found the midpoint which was:
M=( a(2p-1), [a(2p^2 - 2p + 1)]/2 )
then x = a(2p-1)
rearranging to make p the subject
p= (x+a)/2a</span>
I believe it’s 12. But I’m not sure
Answer:
22.75
I did some work to try and find this answer sorry if it is wrong I tried.
