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Phoenix [80]
3 years ago
8

What is the value of x in the matrix equation below? -2 1 2 3

Mathematics
1 answer:
lesya692 [45]3 years ago
4 0

Answer: 2

Step-by-step explanation:

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The net of square pyramid is shown below. What is the surface area of the pyramid?
miv72 [106K]
The surface area of that pyramid is 192 cm^2
4 0
3 years ago
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Please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Anon25 [30]

Answer:

A) 40

B) 20

Step-by-step explanation:

By <em>Length · Width · Height</em>

A)  (5) · (4) · (2) = 40

For part B, the length and width are the same, but the depth (height) of the water is only one foot, so we can replace the height value from the first equation with 1.

B) (5) · (4) · (1) = 20

3 0
2 years ago
Which fraction is the smallest? A. 5⁄6 B. 2⁄3 C. 3⁄5 D. 11⁄15
BabaBlast [244]

Answer:

C

Step-by-step explanation:

5/6=0.83

2/3=0.66

3/5=0.60

11/15=0.73

by changing them to a decimal you get a better look at the amounts they are work and it puts them in a common value.From this you can see that 3/5 is the lowest fraction form the groups so your answer would be <u>C</u>

6 0
3 years ago
Read 2 more answers
Suppose that θ is an acute angle of a right triangle and that sec(θ)=52. Find cos(θ) and csc(θ).
insens350 [35]

Answer:

\cos{\theta} = \dfrac{1}{52}

\csc{\theta} = \dfrac{52}{\sqrt{2703}}

Step-by-step explanation:

To solve this question we're going to use trigonometric identities and good ol' Pythagoras theorem.

a) Firstly, sec(θ)=52. we're gonna convert this to cos(θ) using:

\sec{\theta} = \dfrac{1}{\cos{\theta}}

we can substitute the value of sec(θ) in this equation:

52 = \dfrac{1}{\cos{\theta}}

and solve for for cos(θ)

\cos{\theta} = \dfrac{1}{52}

side note: just to confirm we can find the value of θ and verify that is indeed an acute angle by \theta = \arccos{\left(\dfrac{1}{52}\right)} = 88.8^\circ

b) since right triangle is mentioned in the question. We can use:

\cos{\theta} = \dfrac{\text{adj}}{\text{hyp}}

we know the value of cos(θ)=1\52. and by comparing the two. we can say that:

  • length of the adjacent side = 1
  • length of the hypotenuse = 52

we can find the third side using the Pythagoras theorem.

(\text{hyp})^2=(\text{adj})^2+(\text{opp})^2

(52)^2=(1)^2+(\text{opp})^2

\text{opp}=\sqrt{(52)^2-1}

\text{opp}=\sqrt{2703}

  • length of the opposite side = √(2703) ≈ 51.9904

we can find the sin(θ) using this side:

\sin{\theta} = \dfrac{\text{opp}}{\text{hyp}}

\sin{\theta} = \dfrac{\sqrt{2703}}{52}}

and since \csc{\theta} = \dfrac{1}{\sin{\theta}}

\csc{\theta} = \dfrac{52}{\sqrt{2703}}

4 0
3 years ago
How can I solve this?!
Nutka1998 [239]

A

evaluate f(5) and f(2)

f(5) = 5m + b and f(2) = 2m + b, hence

f(5) - f(2) = 5m + b - 2m - b = 3m

the expression simplifies to

\frac{3m}{3} = 2 ( cross- multiply )

3m = 6 ( divide both sides by 3 )

m = 2 → A




8 0
3 years ago
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