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laila [671]
3 years ago
6

Please help me answering this question WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
ra1l [238]3 years ago
5 0

The answer you are looking for is 1.

When you divide a fraction by another fraction, you flip the second one (make it the reciplical) and multiply straight across. 1/2 * 2/1 = 2/2, which simplified (divided by 2/2) is 1.

I hope this helps!

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HELP ON GEOMETRY!!! PHOTO ATTACHED
Lorico [155]

Answer: 91 degrees.

Step-by-step explanation:

The quadrilaterals shown in the image are <em>similar.</em>

This means:

- The shape of the two quadrilaterals are identical.

- The corresponding angle measures of the two quadrilaterals are identical.

- The size of each side is proportionally identical to the corresponding sides of the other quadrilateral.

As the corresponding angle measures are identical, you can see that both m∠s and m∠j are 55 degrees. All other corresponding angles are identical, too, so:

m∠j = m∠s

m∠g = m∠r

m∠h = m∠q

m∠i = m∠p

We are trying to find m∠q, which is equal to m∠h. m∠h is shown to be 91 degrees in the quadrilateral on the left, so this is the correct answer.

5 0
2 years ago
Read 2 more answers
Find the distance between (-8, -1) and (0, 5). Give your answer in simplest radical form.
dolphi86 [110]

Answer:

D (10)

Step-by-step explanation:

The difference in the x-values is 8 and the difference in y-values is 6; if we draw a line for each difference and connect the points, we get a right triangle. Use pythagorean's theorem of a^2 + b^2 = c^2; 36 (6^2) + 64 (8^2) = 100 (10^2). Square root 100 to get 10

5 0
3 years ago
Enter five expressions: a sum, a difference, a product, a quotient, and one that involves at least two operations that have the
Sever21 [200]

Answer:

i dk

Step-by-step explanation:

i am unable to can answer this i neeed points

3 0
3 years ago
Prove that, tan θ ( 1 + cot ^ 2 θ ) / ( 1 + tan ^ 2 θ ) = cot θ
Gekata [30.6K]

Answer:

(identity has been verified)

Step-by-step explanation:

Verify the following identity:

tan(θ) (cot(θ)^2 + 1)/(tan(θ)^2 + 1) = cot(θ)

Multiply both sides by tan(θ)^2 + 1:

tan(θ) (cot(θ)^2 + 1) = ^?cot(θ) (tan(θ)^2 + 1)

(cot(θ)^2 + 1) tan(θ) = tan(θ) + cot(θ)^2 tan(θ):

tan(θ) + cot(θ)^2 tan(θ) = ^?cot(θ) (tan(θ)^2 + 1)

cot(θ) (tan(θ)^2 + 1) = cot(θ) + cot(θ) tan(θ)^2:

tan(θ) + cot(θ)^2 tan(θ) = ^?cot(θ) + cot(θ) tan(θ)^2

Write cotangent as cosine/sine and tangent as sine/cosine:

sin(θ)/cos(θ) + sin(θ)/cos(θ) (cos(θ)/sin(θ))^2 = ^?cos(θ)/sin(θ) + cos(θ)/sin(θ) (sin(θ)/cos(θ))^2

(sin(θ)/cos(θ)) + (cos(θ)/sin(θ))^2 (sin(θ)/cos(θ)) = cos(θ)/sin(θ) + sin(θ)/cos(θ):

cos(θ)/sin(θ) + sin(θ)/cos(θ) = ^?(cos(θ)/sin(θ)) + (cos(θ)/sin(θ)) (sin(θ)/cos(θ))^2

(cos(θ)/sin(θ)) + (cos(θ)/sin(θ)) (sin(θ)/cos(θ))^2 = cos(θ)/sin(θ) + sin(θ)/cos(θ):

cos(θ)/sin(θ) + sin(θ)/cos(θ) = ^?cos(θ)/sin(θ) + sin(θ)/cos(θ)

The left hand side and right hand side are identical:

Answer: (identity has been verified)

3 0
3 years ago
Y=3x+5 and y=3x-10
Leno4ka [110]
Okay..,
 actually there is some mistake in the problem..!!

as only the content term is changed for both the equation while X and Y are same..

please provide correct question
7 0
3 years ago
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