Answer:
see below
Step-by-step explanation:
The graph has two parts. There is one line for x < 2. It has a slope of 1 and a y-intercept of 0.
The line for x > 2 is the horizontal line x=2.
The point at x=2 is not defined by the function you have posted here, so there is a "hole" in the graph at that point.
Keywords:
<em>Equation, variable, value, clear
</em>
For this case we have an equation with a variable of the form
. Where
. Given the value of
, we want to find the value of the variable "x". So, we have:

We must clear "x", for this, we add "19" to both sides of the equation:

We divide between "3" on both sides of the equation:

Thus, the value of the variable "x" is 30.
Answer:

Option A
Solution:
(6y^2-9y+4)-(-7y^2+5y+1)
Distribute to get rid of ( )
6y^2-9y+4+7y^2-5y-1
Combine like terms
13y^2-14y+3
Answer:
See attached
Step-by-step explanation:
Given function:
Table and graph are attached
Zeros are included in the graph
<u>Zero's are obtained:</u>
x = 0 ⇒ y = 8
y = 0 ⇒ Solving quadratic equation
- -2x² + 5x + 8 = 0
- x = (-5 ± √(25 + 2*4*8))/-4
- x = 3.608
- x = -1.108
So zeros are (0, 8), (3.608, 0) and (-1.108, 0)
Answer:
x = 62
Step-by-step explanation:
62 and x are alternate exterior angles and alternate exterior angles are equal when the lines are parallel