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Anton [14]
2 years ago
14

Scott takes a walk around the block. How far did he walk?

Mathematics
1 answer:
goldfiish [28.3K]2 years ago
7 0
I’m pretty sure it’s 240 because you multiply then add
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Pls help me with this question it wold be great help its circumference
Ivan

Answer:

C = 9.42\ m

Step-by-step explanation:

The formula for the circumference of a circle with the diameter is:

C = \pi d

Since the diameter is 3m, solve for C:

C = \pi d\\C = \pi3\\C = (3.14) \times 3\\C = 9.42

6 0
2 years ago
Read 2 more answers
What is the width of a rectangle with an area of 5/8 in. squared and a length of 10 inches?
Ad libitum [116K]
5/8=10×w this is my equation then i divide by 10 on both sides
w=6.25
6 0
3 years ago
54 x 120575957 divided by 12
ruslelena [56]

542,591,806.5

.............................

4 0
2 years ago
Read 2 more answers
Help please...I don't get this (40 points and I'll give brainliest)
dexar [7]

A x = 0

using the law of exponents a^{0} = 1

for (6² )^ x = 1 then x = 0

B note that 6^{0} = 1 ⇒ x = 1

2 → 2^8 × 3^(-5) × 1^(-2) × 3^(-8) × 2^(-12) × 2^(28)

= 2^(8 -12 + 28) × 1 × 3^(- 5 - 8)

= 2^24 × 3^(- 13) = 2^(24)/3^(13) = 10.523 ( 3 dec. places)




6 0
3 years ago
A University wanted to find out the percentage of students who felt comfortable reporting cheating by their fellow students. A s
Alla [95]

Answer:

The point estimate for this problem is 0.48.

Step-by-step explanation:

We are given that a University wanted to find out the percentage of students who felt comfortable reporting cheating by their fellow students.

A survey of 2,800 students was conducted and the students were asked if they felt comfortable reporting cheating by their fellow students. The results were 1,344 answered "Yes" and 1,456 answered "no".

<em>Let </em>\hat p<em> = proportion of students who felt comfortable reporting cheating by their fellow students</em>

<u></u>

<u>Now,  point estimate (</u>\hat p<u>) is calculated as;</u>

                               \hat p=\frac{X}{n}

where, X = number of students who answered yes = 1,344

            n = number of students surveyed = 2,800

So, Point estimate (\hat p)  =  \frac{1,344}{2,800}

                                     =  <u>0.48 or 48%</u>

5 0
3 years ago
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