Answer:
![\large\boxed{y=0.6x-3.2}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7By%3D0.6x-3.2%7D)
Step-by-step explanation:
The slope-intercept form:
![y=mx+b](https://tex.z-dn.net/?f=y%3Dmx%2Bb)
m - slope
b - y-intercept
We have
![y=0.6x+3](https://tex.z-dn.net/?f=y%3D0.6x%2B3)
Parallel lines have the same slope. Therefore we have the equation:
![y=0.6x+b](https://tex.z-dn.net/?f=y%3D0.6x%2Bb)
The line passes through the point (-3, -5). Put the coordinates of the point to the equation and solve it for b:
![-5=0.6(-3)+b](https://tex.z-dn.net/?f=-5%3D0.6%28-3%29%2Bb)
<em>add 1.8 to both sides</em>
![-3.2=b](https://tex.z-dn.net/?f=-3.2%3Db)
Finally we have:
![y=0.6x-3.2](https://tex.z-dn.net/?f=y%3D0.6x-3.2)
Answer:
i so want to know this aswell
Step-by-step explanation:
Answer:
a dog
Step-by-step explanation:
Answer:
![a=5\\ \\b=0.5](https://tex.z-dn.net/?f=a%3D5%5C%5C%20%5C%5Cb%3D0.5)
Step-by-step explanation:
Given the exponential decay function ![y=5\cdot (0.5)^x](https://tex.z-dn.net/?f=y%3D5%5Ccdot%20%280.5%29%5Ex)
When
then
![y=5\cdot (0.5)^0=5\cdot 1=5,](https://tex.z-dn.net/?f=y%3D5%5Ccdot%20%280.5%29%5E0%3D5%5Ccdot%201%3D5%2C)
so the initial amount is ![a=5](https://tex.z-dn.net/?f=a%3D5)
The exponential decay function
has the decay factor ![b.](https://tex.z-dn.net/?f=b.)
In your case, the eexponential decay factor is ![b=0.5](https://tex.z-dn.net/?f=b%3D0.5)