Question

Probability of multiple Events A. B. C. D.

Answer 1

Given that $P(Q)=\dfrac{3}{5},P(R)=\dfrac{1}{3}$

Also,

$P(Q\wedge R)=P(Q)\cdot P(R)=\dfrac{3}{5}\cdot\dfrac{1}{3}=\dfrac{1}{5}$

We can conclude that,

$P(Q\vee R)=P(Q)+P(R)=\dfrac{3}{5}+\dfrac{1}{3}=\boxed{\dfrac{14}{15}}$

The answer is B.

Hope this helps.

r3t40