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IrinaK [193]
3 years ago
15

Probability of multiple Events A. B. C. D.

Mathematics
1 answer:
vladimir2022 [97]3 years ago
6 0

Given that P(Q)=\dfrac{3}{5},P(R)=\dfrac{1}{3}

Also,

P(Q\wedge R)=P(Q)\cdot P(R)=\dfrac{3}{5}\cdot\dfrac{1}{3}=\dfrac{1}{5}

We can conclude that,

P(Q\vee R)=P(Q)+P(R)=\dfrac{3}{5}+\dfrac{1}{3}=\boxed{\dfrac{14}{15}}

The answer is B.

Hope this helps.

r3t40

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