Question

=" \frac{3}{4} \div 2 \frac{5}{8} = " alt=" \frac{3}{4} \div 2 \frac{5}{8} = " align="absmiddle" class="latex-formula">
$\frac{7}{8} \div 3 \frac{1}{2} =$

$14 \div 3 \frac{5}{7} =$

$\frac{4}{9} \div 3 \frac{1}{3} =$

$\frac{5}{6} \div 11 \frac{2}{3} =$

$\frac{2}{3} \div 1 \frac{1}{9} =$

$\frac{4}{15} \div 6 \frac{2}{5} = [/tex[tex] \frac{9}{16} \div 3 \frac{3}{8} =$

$\frac{5}{9} \div 1\frac{1}{3} =$

$28 \div 1 \frac{1}{6} =$

$\frac{4}{5} \div 2 \frac{3}{10} =$

$9 \div 8 \frac{1}{10} =$

Answer 1

"keep-change-flip" is a strategy used to dividing fractions.

always change the mix fraction to a improper fraction and you slove.

I'll do the first one and the rest is basically done the same way.

$\frac{3}{4} \div 2 \frac{5}{8} = \frac{3}{4} \times \frac{21}{4} = \frac{3}{4} \times \frac{4}{21} = \frac{1}{7}$
for the last fraction equation I cross multiply the 4 divided into 4 gives you 1 and the 3 divided into 21 gives you 7.