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kozerog [31]
3 years ago
11

7X plus 32 is greater than 18 Equals

Mathematics
1 answer:
melomori [17]3 years ago
8 0

Answer: ⇒ x>-2

_______________________________________________________

Step-by-step explanation:

7x+32>18=

First you had to subtract by 32 from both sides of equation.

7x+32-32>18-32

Simplify.

7x>-14

Then you divide by 7 from both sides of equation.

\frac{7x}{7}> \frac{-14}{7}

Simplify it's should be the right answer.

x>-2

______________________________________________________

Hope this helps!

Thank you for posting your question at here on brainly.

Have a great day!

_______________________________________________________

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Step-by-step explanation:

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3 years ago
NarStor, a computer disk drive manufacturer, claims that the median time until failure for their hard drives is more than 14,400
Ne4ueva [31]

Answer:

The test statistics is  t  =  -1.727

Step-by-step explanation:

From the question we are told that

The data given is  

   330 620 1870 2410 4620 6396 7822 81028309 12882 14419 16092 18384 20916 23812 25814

 The population mean is  \mu  =  14400

    The  sample  size is  n =  16

  The  null hypothesis is  \mu \le  14400

    The  alternative hypothesis is  H_a  :  \mu > 14400

The sample mean is mathematically evaluated as

  \= x  =  \frac{\sum x_i}{n}

So

   \= x  =  \frac{330+ 620+ 1870 +2410+ 4620+ 6396+ 7822+ 8102+8309+ 12882+ 14419+ 16092+ 18384 +20916+ 23812+ 25814 }{16}

=>  \= x = 10799.9

The  standard deviation is mathematically represented as

      \sigma =\sqrt{\frac{ \sum (x_i - \=x)^2}{n}}

So

\sigma =\sqrt{\frac{(330- 10799.9)^2 + (620- 10799.9)^2+ (1870- 10799.9)^2 +(2410- 10799.9)^2 + (4620- 10799.9)^2 +(6396- 10799.9)^2 +(7822- 10799.9)^2 }{16}}  \ ..

   ..\sqrt{ \frac{(8102 - 10799.9)^2 +(8309 - 10799.9)^2 + (12882 - 10799.9)^2 + (14419 - 10799.9)^2 + (16092 - 10799.9)^2 + (18384 - 10799.9)^2 +(20916 - 10799.9)^2  }{16}} \ ...

  \ ... \sqrt{\frac{(23812 - 10799.9)^2 +(25814 - 10799.9)^2 }{16}}

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  Generally the test statistic is mathematically represented as

  t =  \frac{10799.9- 14400}{ \frac{8340}{\sqrt{16} } }

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     p-value  = P(Z > t) =  P(Z >  -1.727) =  0.95792

 From the values obtained we see that

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