Answer:
below
Step-by-step explanation:
hope it is well understood
For this case we must solve the following equation:
If we apply cubic root to both sides of the equation, then we eliminate the exponent on the left side:
![\sqrt [3] {x ^ 3} = \sqrt [3] {22}\\x = \sqrt [3] {22}](https://tex.z-dn.net/?f=%5Csqrt%20%5B3%5D%20%7Bx%20%5E%203%7D%20%3D%20%5Csqrt%20%5B3%5D%20%7B22%7D%5C%5Cx%20%3D%20%5Csqrt%20%5B3%5D%20%7B22%7D)
That is the exact solution of the equation. Its decimal solution is given by:
![x = \sqrt [3] {22} = 2.8020](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%20%5B3%5D%20%7B22%7D%20%3D%202.8020)
ANswer:
The solution to the equation is
Let’s start this off by assigning some variables. Let’s have q stand for the amount of quarters while n stands for the amount of nickels.
To start this problem, you need to utilize a system of equations. First, we know that there’s a certain number of quarters and a certain number of nickels and together there’s 63 quarters and nickels.
q + n = 63
We also know that there’s $13.15 in the jar. Since we know the value of the quarters and nickels, we can turn this into another equation.
.25q + .05n = 13.15
And there’s are two equations. Next, we have to solve for one of the variables. Either one works, but I’m going to be using q. I’m going to take the first equation since it’s easier to work with and isolate the q on one side by subtracting n from both sides.
q = 63 - n
Using that new definition for the q variable, we can substitute that into the second equation by replacing q there.
0.25(63 - n) + .05n = 13.15
Now we just need to simplify and solve for n. First we multiply both of the terms inside of the parenthesis by the .25 coefficient
15.75 - .25n + .05n = 13.15
Combine like terms
15.75 - .2n = 13.15
Add .2n to both sides to make the coefficient positive
15.75 = 13.15 + .2n
Subtract 13.15 from both sides to isolate the variable
2.60 = .2n
And finally divide both sides by .2 to solve for n.
13 = n
Now we have the amount of nickels that are in the jar. To solve for the amount of quarters is simple: Put the n value into the first equation and solve for q.
13 + q = 63
And then subtract 13 from both sides for the only step in solving for q.
q = 50.
Leaving us with a solution of 50 quarters and 13 nickels. Both of these variables can be inserted into the second equation to double check the work, but it comes out as even on both sides proving that this is the correct answer.
Hope this helped!
462,093 round to the nearest ten thousand is 60,000 because 2 is less and 6 is greater so 6 stay the same
Answer:
Step-by-step explanation:
a. The probability of selecting a 6 from the first draw and a 7 on the second draw when two balls are selected without replacement from a container with 10 balls numbered 1 to 10
Not independent because without replacement
Prob for both = 
b. The probability of selecting a 6 on the first draw and a 7 on the second draw when two balls are selected with replacement from a container with 10 balls numbered 1 to 10
Here independent because with replacement makes probability independent.
Prob for both = P(A) *P(B) = 
d
c. The probability that two people selected at random in a shopping mall on a very busy Saturday both have a birthday in the month of June. Assume that all 365 birthdays are equally
likely, and ignore the possibility of a February 29 leap-year birthday.
Here independent because one person birthday will not affect the other person birthday
Prob for both = 
d. The probability that two socks selected at random from a drawer containing 10 black socks and 6 white socks will both be black
Prob for I sock black = 10/16 and II sock black if first sock is black = 9/15
Hence not independent
Prob for both = 
