Answer:
Correct Answer is B. The first equation in B is the sum of the equations in A, while the other is obtained by multiplying the first equation in A by 2.
Step-by-step explanation:
As given,
A : 6x + 8y = -10 .......equation (1)
2x - 5y = 12 .......equation (2)
B : 8x + 3y = 2 .......equation (1)
12x + 16y = - 20 .......equation (1)
Correct Answer is B. The first equation in B is the sum of the equations in A, while the other is obtained by multiplying the first equation in A by 2.
Proof :
The first part says that ,
Sum of equation (1) of A and equation (2) of A = Equation (1) of B
Firstly , find the Sum of equation (1) of A and equation (2) of A
⇒6x + 8y + 2x - 5y = -10 + 12
⇒8x + 3y = 2
this is same as equation (1) of B
So, it satisfies the first part
The second part says that,
The equation (2) of B is obtained by multiplying the first equation in A by 2.
It means , if the equation (1) is multiplied by 2 = equation (2) of B
Firstly , if the equation (1) is multiplied by 2 , we get
2 ( 6x + 8y = -10 )
⇒ 2 ( 6x + 8y ) = 2 ( -10)
⇒ 12x + 16y = -20
this is same as equation (2) of B
So, it satisfies the second part.
