Point A. (1,6)
point B.(7,8)
point C (6,3)
Alrighty
squaer base so length=width, nice
v=lwh
but in this case, l=w, so replace l with w
V=w²h
and volume is 32000
32000=w²h
the amount of materials is the surface area
note that there is no top
so
SA=LW+2H(L+W)
L=W so
SA=W²+2H(2W)
SA=W²+4HW
alrighty
we gots
SA=W²+4HW and
32000=W²H
we want to minimize the square foottage
get rid of one of the variables
32000=W²H
solve for H
32000/W²=H
subsitute
SA=W²+4WH
SA=W²+4W(32000/W²)
SA=W²+128000/W
take derivitive to find the minimum
dSA/dW=2W-128000/W²
where does it equal 0?
0=2W-1280000/W²
128000/W²=2W
128000=2W³
64000=W³
40=W
so sub back
32000/W²=H
32000/(40)²=H
32000/(1600)=H
20=H
the box is 20cm height and the width and length are 40cm
Answer: It is a continuous random variable.
The amount of rain is a continuous random variable because it can take on all of the numbers on a number line.
For example, the actual amount of rain in April could be 1 inch. Or 1.4 inches. Or 1.45 inches. Or 1.452020980234 inches. There are an infinite possibilities for the amount of rainfall.
Answer:
D: 57 + 30x = 150
Step-by-step explanation:
63-3(2-10x)=150
63 - 6 + 30x = 150
57 + 30x = 150
