H_TM is reduced to HALT_TM and as such, HALT_TM is undecidable.
<h3>How to Interpret Machine Language?</h3>
A language is referred to as Decidable or Recursive if there is a Turing machine that accepts and halts on every input string w. This tells us that every decidable language is Turing-Acceptable.
Now, we are told that the halting language is reducible to some language B. This means that it is an undecidability via reduction.
Now, Using the idea that “ If A is undecidable and reducible to B, then B is undecidable.” Suppose R decides HALT_TM, we will construct S to decide ATM .
S = “On input (M, B)
This means that H_TM is reduced to HALT_TM and as such, HALT_TM is undecidable.
Read more about machine language at; brainly.com/question/28026656
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The number is ten. hope it helps
You cant write that as a decimal cus that would equal 7 wich is a whole number
4/10 and 8/20 both are equivalent to 0.400
Answer! :
y = -2x + 5
Step by Step! :
slope intercept form:
y = mx + b
m being slope, b being the y intercept.
To find the slope, use this equation:
y^2 - y^1 / x^2 - x^1
Plug in your points.
(-1) - (7) / (3) - (-1)
-8 / 4
-2 is your slope! (y = -2x + b)
To solve for b, plug in any one of your points and solve for b. Let's use (3, -1)
-1 = -2(3) + b
-1 = -6 + b
5 = b
Your new equation is...
y = -2x + 5
