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Marina86 [1]
4 years ago
9

Is my answer correct? if not please correct me

Mathematics
1 answer:
guapka [62]4 years ago
5 0

Answer:

Yes it is

Step-by-step explanation:


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A sample of n = 16 scores has a mean of M = 40 and a variance of s2 = 64. What is the estimated standard error for the sample me
vaieri [72.5K]

Answer:

S.E = 2

Step-by-step explanation:

Given

Mean = 40

s^2 = 64 ----- variance

n = 16 ------------ sample

Required

Determine the S.E

The estimated standard error (S.E) for the sample mean is calculated using the following formula:

S.E = \frac{SD}{\sqrt n}

Where

SD = Standard\ Deviation

SD = \sqrt {s^2}

SD = \sqrt {64}

SD = 8

So:

S.E = \frac{SD}{\sqrt n}

S.E = \frac{8}{\sqrt{16}}

S.E = \frac{8}{4}

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aleksklad [387]

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<h3>What does the Central Limit Theorem state?</h3>

It states that for a <u>proportion p in a sample of size n</u>, the sampling distribution of sample proportion is approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1 - p)}{n}}, as long as np \geq 10 and n(1 - p) \geq 10.

For the test hpyothesis, two conditions are needed:

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More can be learned about the Central Limit Theorem at brainly.com/question/24663213

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