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3 years ago

Find the length of the missing side. Leave your answer in simplest radical form.

Mathematics

2 answers:

malfutka [58]3 years ago

5 0

Solve for hypotenuse

Hypotenuse = $\sqrt{a^{2}+b^{2}}$

Substitute 3 for A and 4 for B
$\sqrt{3^{2}+4^{2}}$

Solve exponents
3^2 = 9
4^2 = 16
$\sqrt{9+16}$

Add
9 + 16 = 25
$\sqrt{25}$

Solve square root
$\sqrt{25}$ = 5
5 is your answer

Lemur [1.5K]3 years ago

4 0

Answer:

Q1 5

Q2 6

Q3 C(no;13^2+21^2=24^2)

Q4 obtuse

Q5 C (8 2 squared)

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Find the limit. use l'hospital's rule if appropriate. if there is a more elementary method, consider using it. lim x→1 1 − x + l

AfilCa [17]

$\displaystyle\lim_{x\to1}\frac{1-x+\ln x}{1+\cos5\pi x}$

Evaluating the limand directly at $x=1$ gives an indeterminate form $\dfrac00$ . Apply L'Hospital's rule once and we get

$\displaystyle\lim_{x\to1}\frac{-1+\frac1x}{-5\pi\sin5\pi x}$

Again, plugging in $x=1$ returns $\dfrac00$ . Apply the rule once more:

$\displaystyle\lim_{x\to1}\frac{-\frac1{x^2}}{-25\pi^2\cos5\pi x}=\frac1{25\pi^2}\lim_{x\to1}\frac1{x^2\cos5\pi x}$

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3 years ago

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nata0808 [166]

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(-4,-5)

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Step-by-step explanation:

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2 years ago

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10. rhombus abcd has vertices at a(-2, 7), b(8, 7), c(2, -1), and d (-8, -1).

horrorfan [7]

Answer: 80

Step-by-step explanation:

We can use the formula $A=\frac{d_{1}d_{2}}{2}$ , where $d_{1}, d_{2}$ are the lengths of the diagonals.

By the distance formula,

$AC=\sqrt{(-2-2)^{2}+(-1-7)^{2}}=\sqrt{16+64}=4\sqrt{5}\\BD=\sqrt{(-8-8)^{2}+(-1-7)^{2}}=\sqrt{256+64}=8\sqrt{5}$

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2 years ago

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Answer:

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3 years ago

Question 1

gulaghasi [49]

Answer:

217

Step-by-step explanation:

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2 years ago

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