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OlgaM077 [116]
3 years ago
13

Find the length of the missing side. Leave your answer in simplest radical form.

Mathematics
2 answers:
malfutka [58]3 years ago
5 0
Solve for hypotenuse

Hypotenuse = \sqrt{a^{2}+b^{2}}

Substitute 3 for A and 4 for B
\sqrt{3^{2}+4^{2}}

Solve exponents
3^2 = 9
4^2 = 16
\sqrt{9+16}

Add
9 + 16 = 25
\sqrt{25}

Solve square root
\sqrt{25} = 5
5 is your answer
Lemur [1.5K]3 years ago
4 0

Answer:

5

Q1 5

Q2 6

Q3 C(no;13^2+21^2=24^2)

Q4 obtuse

Q5 C (8  2 squared)

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Segment PH is graphed on the coordinate grid where P is (-31,8) and H is (29,-10). Point E is the midpoint of segment PH. If poi
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Answer:

The coordinates of point A are (-11 , 2)

Step-by-step explanation:

- The coordinates of point P are (-31 , 8)

- The coordinates of point H are (29 , -10)

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→ x=\frac{x_{1}+x_{2}}{2} and y=\frac{y_{1}+y_{2}}{2}

∵ E is the mid-point of segment PH

∴ The x-coordinate of point E is x=\frac{-31+29}{2}=-1

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- Point A is graphed \frac{2}{3} of the way along the segment from P to E

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→ x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}} and y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}

∵ Point A divides PE at ratio 2 : 1

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∴ The x-coordinate of point A is x=\frac{(-31)(1)+(-1)(2)}{2+1}= -11

∴ The x-coordinate of point A is -11

∴ The y-coordinate of point A is x=\frac{(8)(1)+(-1)(2)}{2+1}=2

∴ The y-coordinate of point A is 2

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Hope this helps.
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