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tigry1 [53]
3 years ago
15

P(A) = 8/15

Mathematics
1 answer:
In-s [12.5K]3 years ago
6 0

Answer:

Step-by-step explanation:

note :  P(AUB) = p(A)+p(B) - p(A∩B)

P(AUB) = 8/15+6/15- 1/5 = 8/15+6/15-3/15 = 11/15 answer : B

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Which of the following are binomials? check all that apply
Ilia_Sergeevich [38]

Answer: A, D, F

Step-by-step explanation: Binomials are the sums of two terms (the sum two monomials). Therefore those with two terms being added are considered binomials.

5 0
3 years ago
Given the quadratic equation below, determine which situation it could represent? x2 -4x = 60
yarga [219]

Answer:

The solution is x = 10 and x = -6. This quadratic could be represented in factored form as (x - 10)(x + 6) or on a graph with x-intercepts at (10,0) and (-6,0).

Step-by-step explanation:

To solve the quadratic, write the quadratic in standard form and factor the equation.

x² - 4x = 60

x² - 4x - 60 = 0

(x - 10)(x + 6) = 0

x = 10 and x = -6

4 0
3 years ago
Tami spins a spinner with 7 sections. The sections are numbered 1 through 7 and all sections are the same size
dexar [7]

Answer:

1 / 7

Step-by-step explanation:

Number of sections on spinner = 7

Section is numbered 1 to 7

Since the probability of landing on each section is the same:

Probability that spinner lands on 4 :

Probability, p = Required outcome / Total possible outcomes

Required outcome = landing on 4 = 1

Total possible outcomes = (1 to 7) = 7

P(landing on 4) = 1 /7

8 0
3 years ago
Help me please please
ratelena [41]
When dividing same numbers with different exponents (they’re both 10 so this works different than if they were different numbers) you subtract the top exponent by the bottom exponent. So 15-4=11 ultimately making the solution 10^11. Hope this helps :)
4 0
2 years ago
What is the solution to StartFraction 5 over 6 EndFraction x minus one-third greater-than 1 and one-third?
Vikentia [17]

Answer:

The correct answer is x > 2.

Step-by-step explanation:

\dfrac{5}{6} x - \dfrac{1}{3} > 1\dfrac{1}{3}

An inequality compares two quantities unlike an equality. An inequality is written with either a greater than ( > ) or lower than ( < ) or greater than equal to ( \geq ) or less than equal to ( \leq ) signs. We solve the above given inequality to find the solutions of the unknown x.

\dfrac{5}{6} x - \dfrac{1}{3} > 1\dfrac{1}{3} \\\dfrac{5}{6} x - \dfrac{1}{3} > \dfrac{4}{3} \\\dfrac{5}{6} x > \dfrac{1}{3} + \dfrac{4}{3} \\\dfrac{5}{6} x > \dfrac{5}{3}\\x > 2

Firstly we change the right hand side quantity to fraction.

We then transfer the - \frac{1}{3} to the right hand side and add them. The inequality sign does not change as we are simply adding or subtracting terms from both the ends.

Finally we divide both sides with \frac{6}{5} to get the required solution. The inequality sign does not change as we are multiplying both the ends with a positive quantity.

This gives us the answer as x > 2.

6 0
2 years ago
Read 2 more answers
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