1.2mL will be needed to make 50 mL of a 2% solution
<h3>Ratio and proportions</h3>
Ratio are written in form of fractions.
If 50mL is required for a 2% solution, hence;
50% = 2mL
0.05 = 2mL
In order to determine the required mL for a 30% solution, we will have;
30% =x
0.03 = x
Find the ratios
0.5/0.3 = 2/x
Cross multiply
0.5x = 2(0.03)
0.5x = 0.6
x = 0.6/0.5
x = 1.2mL
Therefore 1.2mL will be needed to make 50 mL of a 2% solution
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Answer:
0.85
Step-by-step explanation:
1.37-0.52=0.85
1.your going to look at the squares in the background , now on the bottom they are six squares with a line in the middle. your going to put a dot or line on the bottom line of the triangle on each squares ending point (like if your creating a ruler without the tiny lines)2. Ok now if you take the line in the middle( thats all ready in the triangle) you can say that makes to right angle triangle's ,so the one on the left and the one on the right now the one in the left has three squares ( cause remember you had 6 squares but the line in the middle of the triangle splits the triangle into 2 right angle triangles which makes it 3) your going to take each dot and bring it to the top or head of the triangle and you should be done
hoped it helped !!!
Let the lengths of pregnancies be X
X follows normal distribution with mean 268 and standard deviation 15 days
z=(X-269)/15
a. P(X>308)
z=(308-269)/15=2.6
thus:
P(X>308)=P(z>2.6)
=1-0.995
=0.005
b] Given that if the length of pregnancy is in lowest is 44%, then the baby is premature. We need to find the length that separates the premature babies from those who are not premature.
P(X<x)=0.44
P(Z<z)=0.44
z=-0.15
thus the value of x will be found as follows:
-0.05=(x-269)/15
-0.05(15)=x-269
-0.75=x-269
x=-0.75+269
x=268.78
The length that separates premature babies from those who are not premature is 268.78 days
B: From the origin, move 2 units back, 6 units left, and 7 units up.
