PLEASE HELP ASAP!!! WILL MARK BRAINLIEST!!!!

A gift basket has 2 soaps and 5 lotions and costs $20. A second basket has 6 spas and 15 lotions and cost $60. Is it possible to

kifflom [539]

A second basket has 6 spas--- I think you mean 6 soaps , so i will work with that

Answer:it is not possible to determine the price of the soap with the information given.

Step-by-step explanation:

Let s0ap be represented as x

and lotion be represented as y

2 soaps and 5 lotions costing $20 gives us equation 1 as

2 x+ 5y= 20-------- equation 1

second basket with 6 soaps and 15 lotions and costing $60 gives us equation 2 as

6x + 15y= 60------equation 2

Step 2 -- Solving

2 x+ 5y= 20-------- equation 1

6x + 15y= 60--------equation 2

BY elimination method, we multiply equation 1 by (3)

2x + 5y= 20 x (3)

6x + 15y=60-------equation 3

Subtraction of equation 3 from equation 2 gives us

6x + 15y=60-------equation 3

-6x + 15y= 60--------equation 2

0x +0y=0 which is no solution

Therefore it is not possible to determine the price of the soap

3 0

2 years ago

this year, the winner of the new york marathon ran the 8 kilometer event in 24 minutes. what is the runners unit rate

DedPeter [7]

Based on the given situation above, the given values are 8 kilometers and 24 minutes. To simplify these values, we will come up with the result of 1 km in 3 minutes. Therefore, the winner of the New York marathon ran 0.33 kms per one minute so the runners unit rate is 0.33kms/minute.

3 0

2 years ago

Thirty percent of all customers who enter a department store will make a purchase. Suppose that 6 customers enter the store and

torisob [31]

Answer:

Step-by-step explanation:

Let's use binomial distribution, because we are interested in find the total number of successes in a sequence of n independent experiments.

In probability, a binomial distribution is used in a Bernoulli process. That is, a sequence of experiments of n independent trials, each asking a dichotomous question, that means it only has two answers. One answer is a success (probability: p) and the other is a failure (probability: 1-p). In this case, every customer who enters in the store is the experiment. If they make a purchase is a success event, taking into account that every purchase decision has to be independent.

$P(X=x) = C(n,x)p^{x} (1-p)^{n-x}$

x= total number of success

n= total number of experiments

p=probability of success on an indivual trial

$C(n,x) = \frac{n!}{x!(n-x)!}$

a) x= 5 ------> customers that make a purchase

n= 6 ------> total customers

p=0.3

$p(X=5)= C(6,5)(0.3)^{5} (1-0.3)^{6-5} \\p(X=5)=0.102$

b) At least 3 customers make a purchase. x ≥ 3

$P(X\geq 3)=1-P (X=0)-P(X=1)-P(X=2)\\P(X\geq 3)=1-(C(6,0)(0.3^{0})(0.7)^{6}) - (C(6,1)(0.3^{1})(0.7)^{5}) - (C(6,2)(0.3^{2})(0.7)^{4})\\ P(X\geq 3) = 1-0.11765-0.30253-0.32414\\P(X\geq3)= 0.2557$

c) At most 2 customers make a purchase. x ≤ 2

$P(X\leq2) = P(X=0) + P(X=1) + P(X=2)\\P(X\leq2) = (C(6,0)(0.3^{0})(0.7)^{6}) + (C(6,1)(0.3^{1})(0.7)^{5}) + (C(6,2)(0.3^{2})(0.7)^{4})\\P(X\leq2) = 0.11765-0.30253-0.32414\\P(X\leq2)=0.7443$