Ask question

Ask question

All categories

3 years ago

15

Mary Stevens earns 6 an hour at jod and is entitled to time and a half for overtime and double time on holidays. Last week she w

orked 40 hours of regular time, 61/2 hours of overtime, and 8 hours of holiday time. How much did she earn a.190.75 b.74.37 c.394.50d.140.00

1 answer:

Dennis_Churaev [7]3 years ago

4 0

40 x $6=$240
<span>6.5 x $9=$58.50 </span>
<span>8 x $ 12=$ 96 </span>

<span>Answer $394.50</span>

You might be interested in

X2 - 2xy + y2 when x = 3 and y = 2

luda_lava [24]

Answer:

1

Step-by-step explanation:

Substitute 3 for x and 2 for y:

3^2 - 2(3)(2) + 2^2

= 9 - 12 + 4

= 1

8 0

3 years ago

Read 2 more answers

Components arriving at a distributor are checked for defects by two different inspectors (each component is checked by both insp

Yuliya22 [10]

Complete question is;

Components arriving at a distributor are checked for defects by two different inspectors (each component is checked by both inspectors). The first inspector detects 83% of all defectives that are present, and the second inspector does likewise. At least one inspector does not detect a defect on 34% of all defective components. What is the probability that the following occurs?

(a) A defective component will be detected only by the first inspector?

b) A defective component will be detected by exactly one of the two inspectors?

(c) All three defective components in a batch escape detection by both inspectors (assuming inspections of different components are independent of one another)?

Answer:

A) 0.17

B) 0.34

C) 0

Step-by-step explanation:

a) We are told that the first inspector(A) detects 83% of all defectives that are present, and the second inspector(B) also does the same.

This means that;

P(A) = P(B) = 83% = 0.83

We are also told that at least one inspector does not detect a defect on 34% of all defective components.

Thus;

P(A' ⋃ B') = 0.34

Also, we now that;

P(A ⋂ B) = 1 - P(A' ⋃ B')

P(A ⋂ B) = 1 - 0.34

P(A ⋂ B) = 0.66

Probability that A defective component will be detected only by the first inspector is;

P(A ⋂ B') = P(A) - P(A ⋂ B)

P(A ⋂ B') = 0.83 - 0.66

P(A ⋂ B') = 0.17

B) probability that a defective component will be detected by exactly one of the two inspectors is given as;

P(A ⋂ B') + P(A' ⋂ B) = P(A) + P(B) - 2P(A ⋂ B)

P(A) + P(B) - 2P(A ⋂ B) ; 0.83 + 0.83 - 2(0.66) = 0.34

C) Probability that All three defective components in a batch escape detection by both inspectors is written as;

P(A' ⋃ B') - (P(A ⋂ B') + P(A' ⋂ B))

Plugging in the relevant values, we have;

0.34 - 0.34 = 0

7 0

3 years ago

the concentration of a drug in a patient's bloodstream t hours after the drug was administrated presented by the equation c(t) =

Andrews [41]

The graph of the function has no asymptotes.

<h3>The table of values of c(t)</h3>

The function is given as:

c(t) = 5t - t² + 1

When t = 1, 2, 5, 10;

We have:

c(1) = 5(1) - 1² + 1 = 5

c(2) = 5(2) - 2² + 1 = 7

c(5) = 5(5) - 5² + 1 = 1

c(10) = 5(10) - 10² + 1 = -49

So, the table of values is

t c(t)

1 5

2 7

5 1

10 -49

See attachment for the graph of the function

<u>The domain</u>

From the question, we understand that t represents time.

Time cannot be negative i.e. t ≥ 0
The time does not exceed 5.2 i.e. t ≤ 5.2

So, the domain is 0 ≤ t ≤ 5.2

<u>The range</u>

From the graph, the maximum of the graph is 7.25

So, the range is 0 ≤ f(t) ≤ 7.25

<u>Asymptotes</u>

From the graph, we can see that the graph has no asymptotes.

Read more about domain and range at:

brainly.com/question/10197594

#SPJ1

4 0

2 years ago

Simplify.<br> 8^15 : 8^-3<br> asap please

torisob [31]

Answer:

$8^1^5 = 3.5184372e+13\\8^-^3=0.001953125.$

Step-by-step explanation:

hope this helps.

3 0

2 years ago

Read 2 more answers

Given the following diagram, enter the required information.

devlian [24]

CXB = 40 degrees

I am not positive but from what I have looked up this is the answer.

8 0

3 years ago

Read 2 more answers