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viva [34]
3 years ago
15

Mary Stevens earns 6 an hour at jod and is entitled to time and a half for overtime and double time on holidays. Last week she w

orked 40 hours of regular time, 61/2 hours of overtime, and 8 hours of holiday time. How much did she earn a.190.75 b.74.37 c.394.50d.140.00
Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
4 0
40 x $6=$240 
<span>6.5 x $9=$58.50 </span>
<span>8 x $ 12=$ 96 </span>

<span>Answer $394.50</span>
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Represent the relationship between the total cost and the number of items, if total cost t is proportional to the number n of it
kvv77 [185]

Answer:

t = pn

Step-by-step explanation:

We are to find the relationship between total cost and the number of items.

First we would represent the relationship between total cost and number of items with variables

Let the total cost = t

and the number of items = n

Total cost t is proportional to the number n of items:

t ∝ n

t = kn

where k is constant

Since it is purchased at a constant price p, the constant of proportionality would be p. the k would be replaced with p

t = pn

5 0
3 years ago
Nishi practiced violin for 3 1/2 hours in a 5-day period. How many minutes
Kitty [74]

Answer:

.7 min per day

Step-by-step explanation:

3.5 ÷5=0.7

0.7×5=3.5 or 3 1/2

6 0
3 years ago
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IceJOKER [234]

Answer:

a. Indep. = x, and dependent equals f(x)

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Step-by-step explanation:

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4 0
2 years ago
What are the Values of h and k?
lawyer [7]

Answer:

h=4, k=-2

Step-by-step explanation:

we know that

In the function f(x) the inflection point is at (0,0)

In the function g(x) the inflection point is at (4,-2)

so

the rule of the translation of f(x) to g(x) is equal to

(x,y)-----> (x+4,y-2)

That means-----> the translation is 4 units to the right and 2 units down

The equation of g(x) is equal to

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therefore

h=4, k=-2

5 0
3 years ago
Can anyone do this with steps ..
Harrizon [31]

\\ \sf\longmapsto \displaystyle{\lim_{x\to 0}}\dfrac{sinx-sin3x}{sins3x-sinx}

\boxed{\sf \displaystyle\lim_{x\to 0}\dfrac{f(x)}{g(x)}=\dfrac{\lim_{x\to 0}f(x)}{\lim_{x\to 0}g(x)}}

Now

\\ \sf\longmapsto \displaystyle{\dfrac{\lim_{x\to 0}sinx-\lim_{x\to 0}sin3x}{\lim_{x\to 0}sin3x-\lim_{x\to 0}sinx}}

\boxed{\sf \displaystyle{\lim_{x\to 0}}f(x)=f(a)}

\\ \sf\longmapsto \dfrac{sin0-sin3(0)}{sin3(0)-sin0}

\\ \sf\longmapsto \dfrac{0-0}{0-0}

\\ \sf\longmapsto \dfrac{0}{0}

\\ \sf\longmapsto 0

7 0
3 years ago
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