P(odd) or P(multiple of 5)
When we roll 2 number cubes
all possible outcomes of their sum are 2,3,4,5,6,7,8,9,10,11,12.(11 possible outcomes)
Out of those possible outcomes
3,5,7,9,11 are odd (5 outcomes) and ...
5 and 10 are multiples of 5 (2 outcomes)
Now, P(odd) or P(multiple of 5) really means P(odd) + P (multiple of 5) =
(If we had “and” instead of “or” we multiply)
= (5/11) +(2/11)
=7/11
Probability that both roads from a to b are blocked is the product of the individual probabilities, i.e.
P(~ab)=0.25*0.25=0.0625
Similarly
P(~bc)=0.25*0.25=0.0625
Probability that EITHER one or both of ab and bc are blocked is the sum of the probabilities:
P(~ab ∪ ~bc)=0.0625+0.0625=0.125
(recall that one cannot travel from a to c if either ab or bc is blocked.)
Therefore the probability that there exists an open route from a to c
= P(ac) = 1-P(~ab ∪ ~bc)
= 1 - 0.125
=0.875
Option C: (x+4) and (x-1) are the factors of the equation
Explanation:
Given that the equation is 
We need to determine the factors of the equation.
Splitting the middle term, we get,

Grouping the terms, we have,

Let us factor out the term (x+4), we have,

Thus, the factors of the equation are (x+4) and (x-1)
Hence, Option C is the correct answer.
Answer:
¹²/₇
Step-by-step explanation:
Model ⁴/₇ × 3
Assume that you have three pies, each dived into seven slices.
There are only four slices remaining in each pie, that is, there is ⁴/₇ pie in each pie plate
The picture represents ⁴/₇ × 3.
Model the product
Now, transfer slices to get as many filled pie plates as possible.
Count the total slices.
You have 12 slices, and each slice represents ⅐ of a pie.
You have ¹²/₇ pie.
∴ ⁴/₇ × 3 = ¹²/₇