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kolbaska11 [484]
3 years ago
12

Please help! Any assistance is appreciated

Mathematics
1 answer:
Karolina [17]3 years ago
6 0

Answer:

gasgas....

Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=%5Cleft%28%5Csqrt%7B2%7D%2B1%5Cright%29%5Cleft%285%2B%5Csqrt%7B2%7D%5Cright%29" id="TexFormula
dsp73
<h3>Solution:</h3>

( \sqrt{2}  + 1)(5 +  \sqrt{2}) \\  =  \sqrt{2}  (5 +  \sqrt{2} ) + 1(5 +  \sqrt{2} ) \\  = 5 \sqrt{2}  + 2 + 5 +  \sqrt{2}  \\  = 7 + 6 \sqrt{2}

<h3>Answer:</h3>

7 + 6√2

5 0
3 years ago
Read 2 more answers
IS THIS CORRECT!!!????
yanalaym [24]
So if it has to be simplified, there is only one answer if all of it is positive but it has a solution to do with minus numbers which is -2 (-x-2)
8 0
3 years ago
Decide whether you would use a permutation, a combination, or neither. Next, write the solution using permutation notation or co
Zepler [3.9K]

Answer:

Permutation is used.

No. of arrangements = 1260

Step-by-step explanation:

Permutation is used for choosing & arrangement of  'r' out of 'n' objects, when sequence is important.

Total no. of alphabets in CORRECT = 7

C is repeated twice, R is repeated twice

So, Total No. of arrangements =   <u>7 !</u>

                                                   (2!)(2!)

= 5040 / 4

= 1260

5 0
3 years ago
David, a platform diver, dives into the pool during practice. The height of David above the water at any given time, s, can be m
ella [17]

Check the pictures below.

if we knew the roots/solutions of the equation, we can set h(s) = 0 and solve for "s" to find out how many seconds is it when the height is 0.

if you notice in the first picture, when f(x) = 0, is when the parabola hits a root/solution or the ground, for David he'll be hitting the water surface, and the equation that has both of those roots/solutions conspicuous is

h(s) = -4.9(s - 2)(s + 1).

4 0
3 years ago
How do I solve this out??
GuDViN [60]
<h3>Answer:</h3>

(x, y) = (7, -5)

<h3>Step-by-step explanation:</h3>

It generally works well to follow directions.

The matrix of coefficients is ...

\left[\begin{array}{cc}2&4\\-5&3\end{array}\right]

Its inverse is the transpose of the cofactor matrix, divided by the determinant. That is ...

\dfrac{1}{26}\left[\begin{array}{ccc}3&-4\\5&2\end{array}\right]

So the solution is the product of this and the vector of constants [-6, -50]. That product is ...

... x = (3·(-6) +(-4)(-50))/26 = 7

... y = (5·(-6) +2·(-50))/26 = -5

The solution using inverse matrices is ...

... (x, y) = (7, -5)

7 0
3 years ago
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