All categories

3 years ago

Solve for x -3x+8y= 5 6x - 2y=10 x= 15/7 x=10/7 x=5/7 x=5/2

Mathematics

1 answer:

oee [108]3 years ago

3 0

I got 10/7 hope helped u

You might be interested in

A group of objects or numbers is called

IRISSAK [1]

A group of numbers or objects is literally just called a group.

7 0

2 years ago

Read 2 more answers

Select all irrational numbers.

Maurinko [17]

Answer:

OPTION A

OPTION B

OPTION C

Step-by-step explanation:

Irrational numbers are the subset of real numbers. Their decimal representation neither form a pattern nor terminate.

OPTION A: $\sqrt{\frac{1}{2}}$

This is equal to $\frac{1}{\sqrt{2}}$ .

$\sqrt{2} = 1.414...$ is non-terminating. So, it is an irrational number. Hence, the reciprocal of an irrational number would also be irrational. So, OPTION A is irrational.

OPTION B: $\sqrt{\frac{1}{8}}$

This is equal to $\frac{1}{2\sqrt{2}}$ . Using the same logic as Option A, we regard OPTION B to be irrational as well.

OPTION C: $\sqrt{\frac{1}{10}}$

This is equal to $\frac{1}{\sqrt{5}\sqrt{2}}$ .

Both $\sqrt{5}$ and $\sqrt{2}$ are irrational. So, the product and the reciprocal of the product is irrational as well. So, OPTION C is an irrational number.

OPTION D: $\sqrt{\frac{1}{16}}$

16 is a perfect square and is a rational number. $\frac{1}{\sqrt{16}}$ = $\frac{1}{4}$ . This is equal to 0.25, a terminating decimal. So, OPTION D is a rational number.

OPTION E: $\sqrt{\frac{1}{4}}$

4 is a perfect square as well. $\frac{1}{\sqrt{4}} = \frac{1}{2} = 0.5$ , a terminating decimal. So, OPTION E is a rational number.

5 0

2 years ago

0.125 as a fraction and percentage

tresset_1 [31]

Answer:

1/8 and 12.5%

Step-by-step explanation:

5 0

2 years ago

Find the following:

Butoxors [25]

Answer:

Step-by-step explanation:

Limit refers to the value that the function approaches as the input approaches some value.

We say $\displaystyle \lim_{x\rightarrow a}f(x)=L$ , if f(x) approaches L as x approaches 'a'.

(a)

$\displaystyle \lim_{x\rightarrow 5}\left ( \frac{f(x)-8}{x-5} \right )=4\\\frac{\displaystyle \lim_{x\rightarrow 5}f(x)-\displaystyle \lim_{x\rightarrow 5}8}{\displaystyle \lim_{x\rightarrow 5}x-\displaystyle \lim_{x\rightarrow 5}5}=4\\$

$\frac{\displaystyle \lim_{x\rightarrow 5}f(x)-8}{\displaystyle \lim_{x\rightarrow 5}x-5}=4\\\displaystyle \lim_{x\rightarrow 5}f(x)-8=4\left ( \displaystyle \lim_{x\rightarrow 5}x-5 \right )\\\displaystyle \lim_{x\rightarrow 5}f(x)-8=4\displaystyle \lim_{x\rightarrow 5}x-4(5)\\\displaystyle \lim_{x\rightarrow 5}f(x)-8=4(5)-4(5)\\$

$\displaystyle \lim_{x\rightarrow 5}f(x)-8=20-20=0\\\displaystyle \lim_{x\rightarrow 5}f(x)=8$

(b)

$\displaystyle \lim_{x\rightarrow 5}\left ( \frac{f(x)-8}{x-5} \right )=7\\\frac{\displaystyle \lim_{x\rightarrow 5}f(x)-\displaystyle \lim_{x\rightarrow 5}8}{\displaystyle \lim_{x\rightarrow 5}x-\displaystyle \lim_{x\rightarrow 5}5}=7\\\frac{\displaystyle \lim_{x\rightarrow 5}f(x)-8}{\displaystyle \lim_{x\rightarrow 5}x-5}=7\\$

$\displaystyle \lim_{x\rightarrow 5}f(x)-8=7\left ( \displaystyle \lim_{x\rightarrow 5}x-5 \right )\\\displaystyle \lim_{x\rightarrow 5}f(x)-8=7\displaystyle \lim_{x\rightarrow 5}x-7(5)\\\displaystyle \lim_{x\rightarrow 5}f(x)-8=7(5)-7(5)\\\displaystyle \lim_{x\rightarrow 5}f(x)-8=35-35=0\\\displaystyle \lim_{x\rightarrow 5}f(x)=8$

3 0

3 years ago

Which of the following are solution to 2X squared minus 8X -90

svetlana [45]

Answer:

2(x+5)*(x-9)

Step-by-step explanation:

4 0

3 years ago