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3 years ago

5

What is the slope of the line: y = 2x - 1?

1 answer:

photoshop1234 [79]3 years ago

7 0

Answer:

m=2

Step-by-step explanation:

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2 years ago

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If g(x)=4x^2-16 we’re shifted 9 united to the right and 1 down, what would the new equation be?

Inessa05 [86]

Shown in the graph

<h2>Explanation:</h2>

Using graph tools we can graph the function:

$g(x)=4x^2-16$

which is the red graph shown below. As you can see, this is a parabola. The rule for vertical and horizontal shifts is as follows:

$Let \ c \ be \ a \ positive \ real \ number. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:$

$\bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ h(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ h(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ right \ \mathbf{right}: \\ h(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ left \ \mathbf{left}: \\ h(x)=f(x+c)$

Therefore, If we shift the red graph 9 units to the right and 1 down, our new function (let's call it $h(x)$ ) will be:

$h(x)=4\left(x-9\right)^{2}-16-1 \\ \\ Simplifying: \\ \\ h(x)=4\left(x-9\right)^{2}-17$

This graph is the blue graph below. Let's verify the transformation taking the vertex of the red graph:

$(0,-16)$

By translating the 9 units to the right and 1 down the vertex is also translated by the same rule, so:

$New \ vertex: \\ \\ (0+9,-16-1) \\ \\ (9,-17)$

<h2>Learn more:</h2>

Cubic function: brainly.com/question/13773618#

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3 years ago

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Answer:

10 million out of 10

Step-by-step explanation:

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3 years ago

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Rectangle JKLM is congruent to a 4 inch by 7 inch rectangle. How many different values are possible for the length

MissTica

I believe the answer to your question is three you have to be three usually always three

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3 years ago

What equation is graphed in this figure?

topjm [15]

Answer:

The third equation: $y+2=-3(x-1)$

Step-by-step explanation:

The two points on the line are $(-1,4)$ and $(1,-2)$ .

Slope of the line passing through two points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is given as:

$m=(y_{2} -y_{1})/ (x_{2} -x_{1})$

Here, $(x_{1},y_{1})$ and $(x_{2},y_{2})$ are $(-1,4)$ and $(1,-2)$ .

Therefore, slope is equal to, $m=(-2-4 )/ (1-(-1)$

$m=-6/2$

$m=-3$

Now, equation of a straight line with slope m and points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is given as:

$y-y_{1}=m(x-x_{1})\\y-y_{2}=m(x-x_{2})$

Now, if we use the 2nd form, then $x_{2}=1,y_{2}=-2$ .

So, the equation is given as :

$y-(-2)=-3(x-1)\\y+2=-3(x-1)$

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3 years ago