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goldenfox [79]
3 years ago
8

What is the energy requirement in kJ/mol to transport a proton across the mitochondrial inner membrane in plant cells at night w

hen the outside temperature is 15ºC, the pH differential across this membrane is 1.4 pH units, and the membrane potential of 160 mV. Choose the ONE correct answer.
A. +21.8 kJ/mol
B. +75.4 kJ/mol
C. +23.1 kJ/mol
D. +46.2 kJ/mol
E. -21.8 kJ/mol
F. -23.1 kJ/mol
G. +19.0 kJ/mol
H. +44.6 kJ/mol
Biology
1 answer:
lions [1.4K]3 years ago
4 0

Answer:

C. +23.1 kJ/mol

Explanation:

the formula to use to calculate the energy requirement in kJ/mol to transport a proton across the mitochondrial inner membrane in plant cells is:

ΔGt = RTIn  \frac{C_{2} }{C_1}   + ZFΔV

let's list the values of the data we are being given in the question to make it easier when solving it.

Z= 1

F= 96500C (faraday's constant)

ΔV= 160mV = 0.160V

R= 8.314( constant)

T= 15ºC ( converting our degree Celsius into kelvin, we will have 273.15k+ 15 = 288.15K)

∴ T= 288.15K

Putting it all together in the formula, we have:

ΔGt = 8.314 × 288.15 × 2.303 log \frac{C_{2} }{C_1}  + 1  × 96500 × 0.160

ΔGt = 5517.25   [ -(log(H^{+}_{out} ) + log(H^{+}_{in} )_{in}  +15440

ΔGt  = 5517.25 (pH_{out} - pH_{in}  +15440

Given that the pH  differential gradient  across the membrane is 1.4pH units. It implies that;

ΔGt  = 5517.25 × 1.4 + 15440

=  7724.15 +15440

= 23164.15 Joules/moles

= +23.1 KJ/mole

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