T=(60cos78, 60sin78)
T=(12.47, 58.69)
C=45
d=√((45-12.47)^2+58.69^2)
d≈67.1km
Your answer would be 15. You first would move the "pretend" decimal to the left 2 times. so it would end up being 0.25. So then you would set up your problem. 0.25 x 60 =. Which should give you the answer of 15.
First one C second one D sorry if I’m wrong
<span>2x^2 + 3x + 5 = 0
a = 2 b = 3 and c = 5
x = [-b +-sq root(b^2 -4ac)] / 2a
</span><span>x = [-3 +-sq root(9 -4*2*5)] / 4
x = [-3 +-sq root(9 - 40)] / 4
</span><span>x = -(3 / 4) + sq root (-36) / 4
</span><span>x = -(3 / 4) - sq root (-36) / 4
</span>
Problem 3
This is not an exponential function. If you were to graph this out, you would see a parabola forming. Or at the very least, a parabolic-like curve forms. An exponential curve only increases or only decreases for the entire domain. However, in this case, we have an increasing portion, and then it decreases.
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Problem 4
This is an exponential function. Each time x increases by 1, y is multiplied by 4. The equation that models these points is y = 4^x. Note how the function is strictly increasing and there are no decreasing portions mixed in.
